Ok, I am having problems trying to figure this whole XSL thing out. Here is what my XML doc looks like:
Code:
<leftmenu>
 <menu title="Site">
  <item>Home</item>
  <item>Site Map</item>
  <item>News Archive</item>
  <item>About xElements</item>
  <item>Forums</item>
  <item>Contact</item>
 </menu>
 <menu title="Programming">
  <menu title="C &amp; C++">
   <item>Tutorials</item>
   <item>References</item>
   <item>Forms &amp; Discussions</item>
   <item>Samples &amp; Program</item>
  </menu>
  <menu title="Java">
   <item>Tutorials</item>
   <item>References</item>
   <item>Forms &amp; Discussions</item>
   <item>Samples &amp; Program</item>
  </menu>
 </menu>
 <menu title="Alogithm Archive">
  <item>The Archive</item>
  <item>Search</item>
  <item>Submit new Algorithm</item>
 </menu>
</leftmenu>
As you can see, it is recursive (the second level menu item is parsed the same way as the first level menu). Here is what I am using to parset it out:
Code:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="menu">
 <div class="MenuOFF" onmouseover="on(this)" onmouseou="off(this)" onclick="minmax(this)"><xsl:value-of select="title"/></div>
 <div class="subMenu">
 <xsl:for-each select="menu">
  <xsl:apply-templates/>
 </xsl:for-each>
 <xsl:for-each select="item">
  <xsl:apply-templates/>
 </xsl:for-each>
 </div>
</xsl:template>

<xsl:template match="leftmenu/menu/item">
 <div class="itemOFF" onmouseover="on(this)" onmouseout="off(this)" onclick="lnk('')"><xsl:value-of select="menu/item"/></div>
</xsl:template>

</xsl:stylesheet>
But it doesn't appear to be working. None of the titles in the menu tags show up. Can someone help? Also, how would I print out the text to the item element inside the template for the item element? Thanks a lot. I appreciate it.