if statement for login display

[pinch]

hi all,

am trying to get a login section to only display if the user have not logged in yet, and disappears if they are.

PHP Code:

          <?php if(!(isset($_SESSION['MM_Username'])) { $loging_box = "<td bgcolor='#000000'><form id='form1' name='form1' method='POST' action='<?php echo $loginFormAction; ?>'>";
          $loging_box .= "<span class='style114'>Membership Number<input type='text' name='textfield' /><br />Password</span><input type='text' name='textfield2' />";
          $loging_box .= "<br /><input type='submit' name='Submit' value='Login' /></form></td>";
          echo $loging_box;}
?>

am getting a parse error, on the first line, please help

[Webmonkey]

Please could you post the error you are getting?

[kehers]

Try this:

PHP Code:

<?php
if(!isset($_SESSION['MM_Username'])){
//bracket use round ur isset wrong
$loging_box = "<td bgcolor='#000000'><form id='form1' name='form1' method='POST' action='$loginFormAction'>";
/*this wrong - <?php echo $loginFormAction;?> too*/
$loging_box .= "<span class='style114'>Membership Number<input type='text' name='textfield' /><br />Password</span><input type='text' name='textfield2' />"; 
          $loging_box .= "<br /><input type='submit' name='Submit' value='Login' /></form></td>"; 
          echo $loging_box;
} 
?>

That should fix it.

[pinch]

This is the error code

PHP Parse error: parse error, unexpected '{' in c:\...\XXX.php on line 1

[pinch]

This is the error code

PHP Parse error: parse error, unexpected '{' in c:\...\XXX.php on line 1

[Webmonkey]

its becuase

PHP Code:

<?php if(!(isset($_SESSION['MM_Username']))

Should be. . .

PHP Code:

<?php if(!isset($_SESSION['MM_Username']))

[pinch]

Originally Posted by kehers

Try this:

PHP Code:

<?php
if(!isset($_SESSION['MM_Username'])){
//bracket use round ur isset wrong
$loging_box = "<td bgcolor='#000000'><form id='form1' name='form1' method='POST' action='$loginFormAction'>";
/*this wrong - <?php echo $loginFormAction;?> too*/
$loging_box .= "<span class='style114'>Membership Number<input type='text' name='textfield' /><br />Password</span><input type='text' name='textfield2' />"; 
          $loging_box .= "<br /><input type='submit' name='Submit' value='Login' /></form></td>"; 
          echo $loging_box;
} 
?>

That should fix it.

Hi Thanks, i have fixed the second part, but i am not too sure what you mean by the wrong use of brackets, please can you explain further.

thanks again

[Webmonkey]

he maeans the differnece in my post.

[pinch]

thanks everyone, fixed