Upload script

[fikka]

I need to upload text file from the local machine to the server. The problem is I'm getting only file name, but not the contents. Here is my script:

PHP Code:

printf("<TABLE>\n");    

printf("  <TD NOWRAP>\n");


printf("   <FORM NAME=\"UplForm\" METHOD=\"POST\" ENCTYPE=\"multipart/form-data\" ACTION=\"upload.php\" AUTOCOMPLETE=off>\n");    

printf("  <TD>\n");
printf("    File to upload:\n");
printf("  </TD>\n");
printf("  <TD>\n");

printf("    <INPUT TYPE=file ACCEPT=\"text/plain\" NAME=\"upfile\"  SIZE=\"40\" VALUE=\"Browse\">\n");


printf("  </TD>\n");    
printf("</TABLE>\n");            
printf("    <INPUT TYPE=submit VALUE=\"Upload file:\">\n");        

printf("   </FORM>\n"); 


And all I get in the upload.php script is $upfile = “filename.txt”.
All functions like filesize, file_exists return nothing.

What I'm doing wrong?

[ralph l mayo]

Wrapping all that stuff in printf is a waste of resources and your HTML is kind of a mess, but the PHP part looks ok.

Eg., I changed this to post to itself and added the little snip at the end:

PHP Code:

<FORM NAME="UplForm" METHOD="POST" ENCTYPE="multipart/form-data" ACTION="<?php echo $_SERVER['PHP_SELF']; ?>" AUTOCOMPLETE=off>
<TABLE>        
    <TD>
        File to upload:
    </TD>
    <TD>
        <INPUT TYPE=file ACCEPT="text/plain" NAME="upfile"  SIZE="40" VALUE="Browse">
    </TD>    
</TABLE>            
    <INPUT TYPE=submit VALUE="Upload file:">        
</FORM>
<?php
if (isset($_FILES['upfile']))
{
    print_r($_FILES['upfile']);
}
?>

and I get:

Array
(
    [name] => some.file    // the name of the file on the uploader's computer
    [type] => application/octet-stream
    [tmp_name] => /tmp/php2A8.tmp // the actual file name on disc until you use move_uploaded_file() on it
    [error] => 0
    [size] => 455
)

[fikka]

Originally Posted by ralph l mayo

Wrapping all that stuff in printf is a waste of resources and your HTML is kind of a mess, but the PHP part looks ok.

Eg., I changed this to post to itself and added the little snip at the end:

PHP Code:

<FORM NAME="UplForm" METHOD="POST" ENCTYPE="multipart/form-data" ACTION="<?php echo $_SERVER['PHP_SELF']; ?>" AUTOCOMPLETE=off>
<TABLE>        
    <TD>
        File to upload:
    </TD>
    <TD>
        <INPUT TYPE=file ACCEPT="text/plain" NAME="upfile"  SIZE="40" http://www.codingforums.com/newreply.php?do=newreply&p=410339VALUE="Browse">
    </TD>    
</TABLE>            
    <INPUT TYPE=submit VALUE="Upload file:">        
</FORM>
<?php
if (isset($_FILES['upfile']))
{
    print_r($_FILES['upfile']);
}
?>

and I get:

Array
(
    [name] => some.file    // the name of the file on the uploader's computer
    [type] => application/octet-stream
    [tmp_name] => /tmp/php2A8.tmp // the actual file name on disc until you use move_uploaded_file() on it
    [error] => 0
    [size] => 455
)

Big thnx!

[dniwebdesign]

Edit.... Sorry... replyed when I wanted a new one... <_<