this is my code, and it works great. But now, when the picture changes, the select and buttons move around with it. Is there a way to postion the bottom of the image so that the select and buttons dont move?
PHP Code:
<SCRIPT LANGUAGE="JavaScript">
<!--
function doChange(opt){
var selobj=document.getElementById("piclist");
var idx=selobj.selectedIndex;
if(opt=="back" && idx!=0) idx--;
if(opt=="next" && idx!=selobj.options.length-1) idx++;
selobj.selectedIndex=idx;
document.getElementById("mypic").src=selobj.options[idx].value;
window.status=selobj.options[idx].id;
return true;
}
//-->
</SCRIPT>
</HEAD>
<BODY background="swab.gif" link="maroon"><center>
<p><img id="mypic" src="pic1.jpg"></p>
<input type="button" value="back" onclick='doChange("back")'>
<SELECT id="piclist" onchange='doChange("selected")'>
<option value="pic1.jpg" id="picture 1">Pic1</option>
<option value="pic2.jpg" id="picture 2">Pic2</option>
<option value="pic3.jpg" id="picture 3">Pic3</option>
<option value="whole_world.gif" id="the globe">Globe</option>
<option value="http://www.iflta.org/images/2003_poster_contest_winner.jpg" id="2003 winner">Winner</option>
</SELECT>
<input type="button" value="next" onclick='doChange("next")'>
<p><a href='javascript:window.close();'>Close Window</a></p>
</center></BODY>
</HTML>