SQL syntax error

[chump2877]

Can you find the SQL syntax error in this PHP code:

PHP Code:

<?


$dbcon = mysql_connect("localhost","username","password");

mysql_select_db("MyDatabase",$dbcon);



// Reset index number to zero.

$queryK = "UPDATE user_information SET index_no='0' WHERE username LIKE '%".$_SESSION['username']."%'";
$resultK = mysql_query($queryK);
if (mysql_errno())
{
    die("<br>" . mysql_errno() . ": " . mysql_error() . "<br>");
}


// Drop table $username.

$queryB = "DROP TABLE ".$_SESSION['username']."";
$resultB = mysql_query($queryB);
if (mysql_errno())
{
    die("<br>" . mysql_errno() . ": " . mysql_error() . "<br>");
}



?>

I believe the error is somewhere around this line:

PHP Code:

$queryK = "UPDATE user_information SET index_no='0' WHERE username LIKE '%".$_SESSION['username']."%'"; 


Thanks for any help....

[Brandoe85]

echo out $_SESSION['username'] make sure it has a value. I'm thinking it's with your drop table query.