Don't know if there is one of these online, so I made me own. Simple function that outputs a number as words. First argument is the number, second argument is flag (default = false) that controls whether output is cardinal or ordinal - as in "one" or "first".
Goodness knows if I have the grammer correct, especially when the numbers get big. Enjoy!
LIMITS:
1) Doesn't work with WebTV or below NS 4. Changing the large literal array into a common array should fix that, but I didn't bother.
2) Converts number into an integer before wording number. So, no "one point forty-five" stuff. This function is a good start for anyone who wants to do that though.
3) Always returns, "zero" for 0. Couldn't find cardinal equivalent to "zero"... zeroeth?
Code:
/*
Num2Word, ouputs written number in human language format
ARGUMENTS:
-----------
Nbr: num, the number to be worded. This number is converted into an integer.
Crd: bol, flags whether output is cardinal or ordinal number. Cardinal is used when describing the order of items, like "first" or "second" place.
*/
function Num2Word(num,fmt) {
//_ arguments
num = Math.round(num).toString(); // round value
if (num == 0) return 'zero'; // if number given is 0, return and exit
//_ locals
// word numbers
var wnums = [['hundred','thousand','million','billion','trillion','zillion'],['one','first','ten','','th'],['two','second','twen',0,0],['three','third','thir',0,0],['four','fourth',0,0,0],['five','fifth','fif',0,0],['six','sixth',0,0,0],['seven','seventh',0,0,0],['eight','eighth','eigh',0,0],['nine','ninth',0,0,0],['ten',],['eleven',],['twelve','twelfth'],['thirteen',],['fourteen',],['fifteen',],['sixteen',],['seventeen',],['eighteen',],['nineteen',]];
// digits outside triplets
var dot = (num.length % 3) ? num.length % 3 : 3;
// number of triplets in number
var sets = Math.ceil(num.length/3);
// result string, word as number
var rslt = '';
//_ convert every three digits
for (var i = 0; i < sets; i++) { // for each set of triplets
// capture set of numbers up to three digits
var subt = num.substring((!i) ? 0 : dot + (i - 1) * 3,(!i) ? dot : dot + i * 3);
if (subt != 0) { // if value of set is not 0...
var hdec = (subt.length > 2) ? subt.charAt(0) : 0; // get hundreds digit
var ddec = subt.substring(Math.max(subt.length - 2,0),subt.length); // get double digits
var odec = subt.charAt(subt.length - 1); // get one's digit
// hundreds digit
if (hdec != 0) rslt += ' ' + wnums[hdec][0] + '-hundred ' + ((fmt && ddec == 0) ? 'th' : '');
// add double digit
if (ddec < 20 && 9 < ddec) { // if less than 20...
// add double digit word
rslt += ' ' + ((fmt) ? ((wnums[ddec][1]) ? wnums[ddec][1] : wnums[ddec][0] + 'th') : wnums[ddec][0]);
} else { // otherwise, add words for each digit...
// add "and" for last set without a tens digits
if ((0 < hdec || 1 < sets) && i + 1 == sets && 0 < ddec && ddec < 10) rslt += 'and ';
// tens digit
if (19 < ddec) rslt += wnums[ddec.charAt(0)][(wnums[ddec.charAt(0)][2]) ? 2 : 0] + ((i + 1 == sets && odec == 0 && fmt) ? 'tieth' : 'ty') + ((0 < odec) ? '-' : ' ');
// one's digit
if (0 < odec) rslt += wnums[odec][(i + 1 == sets && fmt) ? 1 : 0];
}
// add place for set
if (i + 1 < sets) rslt += ' ' + wnums[0][sets - i - 1] + ' '; // if not last set, add place
} else if (i + 1 == sets && fmt) { // otherwise, if this set is zero, is the last set of the loop, and the format (fmt) is cardinal
rslt += 'th'; // add cardinal "th"
}
}
//_ return result
return rslt
}
Test the result of various valies like so
Code:
for (var i = 0; i < 50; i++) {
var x = Math.round(Math.random() * 5000000);
document.write(x,' -> ' + Num2Word(x).bold(),'<BR>');
}
Use this function towards whatever means you deem necessary. Pease credit me, Bemi Faison, if you use this script.
- Much obliged.
rawsweets
Last edited by rawsweets; 08-22-2002 at 05:36 PM..
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Number to word translator
