Hello everyone! I was hoping someone might be able to give me a hand with the program I am writing for my intro cs class. We are studying algorithms and implementing them with java. I am totally new to programming, though I DO remember programming my TI-85 graphing calculator to output formulas back in high school several years ago! I am struggling with the code, not the math.
Here is the problem:
for f(x) = 0.1x^3 + 3.6
create an algorithm to find the root of the function and implement it in java
For the algorithm, I am using Newton's Method to find the zero. Newton's Method is:
xn+1
= xn
- ( f(xn
) / ( f'(xn
) )
Here is the code I have written:
Code:
public class root {
public static void main(String[] args) { //begin arguments
//introduce variable u (the "guess" or [x sub n]), variable v ("guess +" or [x sub n+1])
double u=-10000;
double v;
//for function
for(u=-10000; u<=10000; v=(u-(((0.3*u*u*u)+36)/((0.9*u)*(0.9*u)))))
{if ((abs(double u))-(abs(double v)) <= 0.001);
{System.out.println("The root of the function is " );
//I used Newton's Method here. In general terms, the formula is:
//(x sub n+1) = (x sub n) - [ f(x) / f'(x) ]
}
}
}
}
Could someone tell me where I'm going wrong? I want the solution accurate to 0.001. The root is actually appriximately -3.301. It is very frustrating to try to implement algorithms in code when my instructor isn't actually teaching java to the class and just expects us to be able to do it!
--Renee