Don't bother loading if variable requirements not met

[RonnyNishimoto]

I was wonder if there was a way to only load a chunk of the page if a variable is set to something (let's just say "1").

So like:

PHP Code:

<?php
if x == "1" {
   load(#something);
}
?>

<div id="page""></div>
<div id="something"></div>

Thank you!

[tracknut]

Something like this?

<?php
if (x == "1") {
?>

<h1>X was equal to 1</h1>

<?php
}
?>

<div id="page""></div>
<div id="something"></div>

[RonnyNishimoto]

I know everybody is laughing at me right now

Thank you so much tracknut!

[Arcticwarrio]

variables should start with a $
you could just echo it too:

PHP Code:

<?php
if ($x == "1") {
   echo 'something';
}
?>

<div id="page""></div>
<div id="something"></div>

it is also fine inline:

PHP Code:

<div id="page""></div>
<div id="something"><?php if ($x == "1") {echo 'something';}?></div>

[Keleth]

You can also put the content in another page and use include or require to put it in:

PHP Code:

 if ($x == 1) include('path/to/file.ext'); 


Remember you don't need quotes around a number unless that number is explicitly a string... just because PHP is type loose doesn't mean you should be!