Mistake in Calendar and Trying to Find a Way to Not to Choose the Same Random Number

IMayNeed · 06-08-2012, 06:51 PM

Hello to the Coding Forums!

This is my first post!

I am trying to (re)write a calendar which starts on Monday, but days is one day off. For example, September 1st 2012 shows Sunday instead of Saturday and June 8th 2012 shows Saturday instead of Friday. I couldn't find the mistake myself.

Code:

 var monthName = new Array("JANUARY", "FEBRUARY", "MARCH", "APRIL", "MAY", "JUNE", "JULY", "AUGUST", "SEPTEMBER", "OCTOBER", "NOVEMBER", "DECEMBER");

function calendar() {
var calDate = new Date("September 01, 2012");
document.write("<table id='calendar_table'>");
writeCalTitle(calDate);
writeDayTitle();
writeCalDays(calDate);
document.write("</table>");
}

function writeCalTitle(calendarDay) {

var thisMonth = calendarDay.getMonth();
var thisYear = calendarDay.getFullYear();

document.write("<tr>");
document.write("<th colspan='7'>");
document.write("<span id='month'>"+monthName[thisMonth]+" </span><span id='year'>"+thisYear+"</span>");
document.write("</th>");
document.write("</tr>");
}

function writeDayTitle() {
var dayName = new Array("Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun");

document.write("<tr>");
for (var i=0;i<=4;i++){
document.write("<th class='calendar_weekdays'>"+dayName[i]+"</th>");
}

for (var i=5;i<=6;i++){
document.write("<th class='calendar_weekends'>"+dayName[i]+"</th>");
}
document.write("</tr>");
}

function daysInMonth (calendarDay) {
var dayCount = new Array(31,28,31,30,31,30,31,31,30,31,30,31)
var thisYear = calendarDay.getFullYear();
var thisMonth = calendarDay.getMonth();
if(thisYear%4==0){
if((thisYear%100!=0)||(thisYear%400==0)){
dayCount[1]=29;
}
}
return dayCount[thisMonth];
}

function writeCalDays(calendarDay){
var currentDay = calendarDay.getDate();
var totalDays = daysInMonth(calendarDay);
calendarDay.setDate(1);
var weekDay=calendarDay.getDay();
document.write("<tr>");
for (var i=0;i<weekDay;i++){
document.write("<td></td>");
}
var dayCount=1;
while(dayCount<=totalDays){
if (weekDay==0){
document.write("<tr>");
}
if(dayCount==currentDay){
document.write("<td class='calendar_dates' id='calendar_today'>"+dayCount+"</td>");
} else {

document.write("<td class='calendar_dates'>"+dayCount+"</td>");
}
if (weekDay==6){
document.write("</tr>");
}
dayCount++;
calendarDay.setDate(dayCount);
weekDay=calendarDay.getDay();
}
document.write("</tr>");
}

My second question is I am trying to use 11 values from an array of 11 items, but I do want items to be changed at every load, but never be the same at a time (var1!=var2!=!var3...). I am new to javascript and couldn't find the right function to do that. I am just posting the related codes.

Code:

var colors = new Array("aqua","blue","fuchsia","lime","magenta","navy","purple","red","white","yellow","black");
var color1 = randomInteger(10);
var color2 = randomInteger(10);
var color3 = randomInteger(10);
var color4 = randomInteger(10);
var color5 = randomInteger(9);
var color6 = randomInteger(10);
var color7 = randomInteger(10);
var color8 = randomInteger(10);
var color9 = randomInteger(10);
var color10 = randomInteger(10);
var color11 = randomInteger(10);

function randomInteger(size) {
return Math.floor((size+1)*Math.random());
}

function changeColor() {

document.write("h1 {color:"+colors[color1]+"}");

document.write("h2 {color:"+colors[color2]+"}");

document.write("#month {color:"+colors[color3]+"}");

document.write("#year {color:"+colors[color4]+"}");

document.write(".calendar_dates {color:"+colors[color5]+"}");

document.write(".calendar_weekdays {color:"+colors[color6]+"}");

document.write(".calendar_weekends {color:"+colors[color7]+"}");

document.write("#calendar_today {color:"+colors[color8]+"}");

document.write("#clock {color:"+colors[color9]+"}");

document.write("#clock p {color:"+colors[color10]+"}");

document.write("#clock input {color:"+colors[color11]+"}");
}

Now, instead of creating 11 variables, is there any other way that I can use and how can I make it in a way that the colors will be random and never be the same at a time.

color1!=color2!=color3!=color4....

My main question is do I have to create 11 variables or not, the second part is less important.

P.S.: color 5 is randomInteger(9) on purpose; I didn't want it to be black, but if there is an answer to my question but color5 has to be randomInteger(10) instead of randomInteger(9); it is absolutely ok.

Thank you.

Philip M · 06-08-2012, 07:35 PM

Change this line to

Code:

var dayName = new Array("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat");

Day 0 is Sunday, Day 6 is Saturday.

To avoid repetition you need to shuffle your colors into a new order:-

Code:

<script type="text/javascript">

Array.prototype.shuffle = function() {
var s = [];
while (this.length) s.push(this.splice(Math.random() * this.length, 1)[0]);
while (s.length) this.push(s.pop());
return this;
}

var colors = new Array("aqua","blue","fuchsia","lime","magenta","navy","purple","red","white","yellow","black");
colors.shuffle();

alert (colors);  // the shuffled array

for (var i =0; i<colors.length; i++) {
alert (colors[i]);
}

</script>

As has often been stated in this forum, document.write() is in effect obsolete. document.write() statements must be run before the page finishes loading. Any document.write() statement that runs after the page finishes loading will create a new page and overwrite all of the content of the current page (including the Javascript which called it). So document.write() is at best really only useful to write the original content of your page. It cannot be used to update the content of your page after that page has loaded. Use DOM methods instead.

Quote:

I am new to java..

Be aware that Java and Javascript are entirely different programming languages, in spite of the confusingly similar names. Rather like Austria and Australia!

"Let us be thankful for the fools. But for them the rest of us could not succeed. " - Mark Twain, US humorist, novelist, short story author, & wit (1835 - 1910)

felgall · 06-09-2012, 12:17 AM

Quote:

Originally Posted by iBall

<offTopic style="Tip">

In that case using document.write() is fine for this purpose to help students quickly get output to the browser while learning the basics of javascript.

As soon as you start learning more about the Document Object Model (DOM), you really should then use more appropriate DOM methods to output to the browser.

document.write outputs to the current page only while it is still loading. If called after the the page has loaded, it will output to a new page. document.write is really only useful for writing to child pages.

</offTopic>

Using innerHTML is far more straightforward and less error prone for beginners to use than document.write is - there's no reason for using the more complicated document.write rather than innerHTML except in those advanced userscripts where document.write is the only way that works.

There are far fewer situations where innerHTML will break the web page functionality compared to the ways that document.write can break the functionality.

Of course the way that always works is to use the proper DOM commands that make up about 60% of JavaScript but learning those is a bit more complex and since innerHTML will work most of the time it is the obvious choice for beginners to use first.

IMayNeed · 06-09-2012, 12:29 AM

Thanks for the shuffle suggestions.

When I make the days array start with Sunday, how can I change the code to create a monthly calendar that starts with Monday?

Yes, I am a student. And, the only internet I have is at school so most of the time, I have to use books and downloaded scripts to work.

felgall · 06-09-2012, 12:45 AM

Quote:

Originally Posted by IMayNeed

When I make the days array start with Sunday, how can I change the code to create a monthly calendar that starts with Monday?

See http://javascript.about.com/library/blweekstart.htm

Krupski · 06-09-2012, 01:13 AM

Quote:

Originally Posted by IMayNeed

I am trying to (re)write a calendar which starts on Monday, but days is one day off. For example, September 1st 2012 shows Sunday instead of Saturday and June 8th 2012 shows Saturday instead of Friday.

To find the day of the week for any date, use Zeller's Congruence ( LINK ).

My implementation in Javascript:

Code:

/***
 * zeller's congruence
 * returns day of week (0=Sunday, 1=Monday, etc...)
 ***/
function zeller (day, month, year) {
    var dow = -1;
    if (3 > month) {
        month += 12;
        year -= 1;
    }
    dow += day;
    dow += parseInt(((month + 1) * 26) / 10);
    dow += year;
    dow += parseInt(year / 4);
    dow += (6 * parseInt(year / 100));
    dow += parseInt(year / 400);
    return dow % 7;
};

Hope this is of some help to you.......

felgall · 06-09-2012, 01:59 AM

Quote:

Originally Posted by Krupski

To find the day of the week for any date, use Zeller's Congruence ( LINK ).

My implementation in Javascript:

Code:

/***
 * zeller's congruence
 * returns day of week (0=Sunday, 1=Monday, etc...)
 ***/
function zeller (day, month, year) {
    var dow = -1;
    if (3 > month) {
        month += 12;
        year -= 1;
    }
    dow += day;
    dow += parseInt(((month + 1) * 26) / 10);
    dow += year;
    dow += parseInt(year / 4);
    dow += (6 * parseInt(year / 100));
    dow += parseInt(year / 400);
    return dow % 7;
};

Hope this is of some help to you.......

It is far easier to just use the built in date object - load the date and retrieve the day. All you need to do to get the day of the week with Monday as 0 and Sunday as 6 is to use:

Code:

Date.prototype.mGetDay = function() {
 return (this.getDay() + 6) %7;
 }
dayOfWeek = new Date(year, month-1, day).mGetDay();

Also you are misusing parseInt in that code where you should be using Number() (which is really only needed around the (month+1) part if you are passing the month astext instead of as a number - you don't need to convert to base 10 anywhere in that function and so it doesn't need parseInt at all.

Krupski · 06-09-2012, 02:44 AM

Quote:

Originally Posted by felgall

Also you are misusing parseInt in that code where you should be using Number() (which is really only needed around the (month+1) part if you are passing the month astext instead of as a number - you don't need to convert to base 10 anywhere in that function and so it doesn't need parseInt at all.

That code snippet is just a standard algorithm I use for my own stuff here. I have the same code in C, Intel ASM, Mototola ASM, GWBASIC and Javascript.

I do need parseInt because the algorithm depends on integer math and indeed fails if floating point numbers get involved.

If, for example, part of the algorithm does "1987 / 4", the result (496.75) would propagate through and produce an incorrect day of week. So I have to force JS to act as though all numbers are (INT).

For fun, make an array of day names, then run the JS code and plug in well known dates (Dec 7, 1941 - Sep 11, 2001, - etc...) and see what happens with and without "parseInt".

Edit:
How's this for some wild code?

Code:

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; clockset.asm - sets smartclocks ; (c) 1996, 2010 roger a. krupski ; Thu 01/14/2010 17:31:45 ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; clock equ $a000 ;clock memory mapped address ; offsets into clkbuf (smartclock data - see below) centi equ 0 ;centiseconds offset secs equ 1 ;seconds offset mins equ 2 ;minutes offset hours equ 3 ;hours offset day equ 4 ;osc/rst/day offset date equ 5 ;date offset month equ 6 ;month offset year equ 7 ;year offset regbs equ $1000 ;register base scsr equ regbs+$2e ;sci status reg scdr equ regbs+$2f ;sci data reg ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; program starts here ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; org $2000 ;program in sram jmp start ;jump around smartclock driver ; include m4859.asm ;driver for st micro ; include ds-1215.asm ;driver for smart-ram include ds-1216.asm ;driver for smart-rom start ldaa #' ' ;a = space ldab #bufsiz ;buffer size ldx #buffer ;point to input buffer clrbuf staa 0,x ;erase buffer inx ;bump pointer decb ;count down bne clrbuf ;do the rest clrb ;b=0 stab curpos ;init cursor position to 0 ldx #msg1 ;point to prompt jsr outstrg ;display it ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; this is the main user input loop ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; main jsr input ;read serial term beq main ;wait for a key cmpa #3 ;ctrl-c? beq exit ;yes, exit cmpa #27 ;escape? bne main2 ;no, run program exit ldx #msg3 ;point to abort message jsr outstrg ;print it swi ;ctrl-c received, exit! main2 cmpa #13 ;c/r? beq setit ;yes, set the clock! cmpa #8 ;backspace? beq do_bs ;yes, do it ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; here all controlling characters have been tested ; for. now we look for valid input such as spaces ; and numbers 0 thru 9. if not, we just ignore them. ; if matched, placed in the buffer. ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; cmpa #' ' ;space? beq char ;yes, add to buffer cmpa #'0' ;number? blo main ;no, ignore cmpa #'9' ;number? bhi main ;no, ignore ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; legal character found, write it to buffer ; legal character is either a space or 0 thru 9 ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; char ldx #buffer ;point to buffer ldab curpos ;get cursor position cmpb #prlen ;at end? bhs chrout ;at end, can't do anything abx ;x points to current char staa 0,x ;write char to buffer incb ;move fwd 1 position stab curpos ;update cursor position jsr output ;echo char to term chrout jmp main ;return to main loop ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; do backspace ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; do_bs ldx #buffer ;point to buffer ldab curpos ;get cursor position beq dobsout ;at beginning, can't do anything decb ;backup 1 position stab curpos ;update cursor position abx ;x points -> current char in buffer ldaa #' ' ;a = space staa 0,x ;erase char in buffer ldaa #8 ;load backspace jsr output ;print backspace to term ldaa #' ' ;load a space jsr output ;erase char on term ldaa #8 ;load backspace jsr output ;backup cursor on term dobsout jmp main ;return to main loop ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; done getting input, attempt to set the clock! ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; setit ldx #buffer+hro ;hour input ldy #clkbuf+hours ;hour for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #23 ;legal? bhi badval ;no, abort! ldx #buffer+mio ;minutes input ldy #clkbuf+mins ;minutes for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #59 ;legal? bhi badval ;no, abort! ldx #buffer+sco ;seconds input ldy #clkbuf+secs ;seconds for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #59 ;legal? bhi badval ;no, abort! ldy #clkbuf+centi ;centi for clock clr 0,y ;default to zero ldx #buffer+dao ;date input ldy #clkbuf+date ;date for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #1 ;legal? blo badval ;no, abort cmpb #31 ;legal? bhi badval ;no, abort! ldx #buffer+mno ;month input ldy #clkbuf+month ;month for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #1 ;legal? blo badval ;no, abort cmpb #12 ;legal? bhi badval ;no, abort! ldx #buffer+yro ;year input (last 2 digits) ldy #clkbuf+year ;year for clock jsr conv ;convert 2 ascii to 1 packed bcd cmpb #99 ;legal? bhi badval ;no, abort! jsr dayweek ;get day of week (0=sunday) andb #%00000111 ;strip unused bits orab #%00010000 ;"or" in osc enable for dallas stab clkbuf+day ;set osc, reset and d.o.w. bra setclk ;set clock clock & swi ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; arrive here if invalid data (like "hour 90" is illegal) ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; badval ldx #msg4 ;bad value jsr outstrg ;print it swi ;return to monitor ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; actually set the clock from the buffer here ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; setclk ldx #clkbuf ;point to buffer ldy #clock ;point to clock chip ldaa #0 jsr doclk ;write time to clock ldx #verbuf ;point to verify buffer ldy #clock ;point to clock chip ldaa #1 jsr doclk ;read time back ldx #msg2 ;"data verify...." jsr outstrg ;print it ldx #clkbuf ;point to write buffer ldy #verbuf ;point to read buffer ldab #8 ;bytes to verify verf cpx #clkbuf+centi ;the "centiseconds" byte? beq verf2 ;yes, skip test cpx #clkbuf+day ;the "day" byte? beq verf2 ;yes, skip test ldaa 0,x ;get a byte cmpa 0,y ;match? bne fail ;yes verf2 inx ;bump... iny ;...pointers decb ;count down bne verf ;check rest ldx #msg2s ;"...success!" showit jsr outstrg ;print it swi ;return to buffalo fail ldx #msg2f ;"...failed!" bra showit ;print it ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; convert 2 ascii bytes to one packed bcd number ; for the clock and also to one hex number ; for range validation. ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; conv psha pshx ;save registers ldab 0,x ;get hi byte cmpb #' ' ;space? bne conv2 ;no, leave it ldab #'0' ;yes, convert to zero conv2 subb #'0' ;ascii -> decimal aslb ;slide up to... aslb aslb aslb ;...hi nybble ldaa 1,x ;get lo byte cmpa #' ' ;space? bne conv3 ;no, leave it ldaa #'0' ;yes, convert to zero conv3 suba #'0' ;ascii -> decimal aba ;a+b->a tab ;a->b stab 0,y ;store to clock buffer bsr bcd2dec ;convert bcd to decimal pulx pula ;restore registers rts ;return with decimal in b ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; packed bcd to decimal converter ; ; entry: b = bcd number 00-99 ; exit : b = decimal equivalent ; example: entry b=$50, exit b=$32 (decimal 50) ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; bcd2dec psha ;save a pshb ;b on stack lsrb ;shift hi... lsrb ;...nibble down... lsrb ;...to lower... lsrb ;...nibble ldaa #6 ;a=6 mul ;make conversion factor negb ;make factor negative pula ;restore b into a aba ;add negative = subtract positive tab ;a->b (result to b) pula ;restore a rts ;return to caller ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; here we find the day of week as 0 thru 6 ; 0 thru 6 where 0=sunday, 1=monday, etc... ; using dr. christian zeller's congruence. ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; dayweek ldx #clkbuf ;point to raw clock data ldab month,x ;get bcd month jsr bcd2dec ;convert to decimal pshb ;month->stack ldab date,x ;get bcd day jsr bcd2dec ;convert to decimal pshb ;day->stack clra ;zero top of d ldab year,x ;get bcd year jsr bcd2dec ;convert to decimal addd #2000 ;convert to full year pshb psha ;year->stack pulx ;year->x pulb ;day->b pula ;month->a ;; fall through to zeller, then rts with data ;; stack offsets offset 0 mn ds.w 1 ;temp month dy ds.w 1 ;temp day yr ds.w 1 ;temp year tmp ds.w 1 ;intermediate results ssiz equ *-mn ;storage size astack ds.b 1 ;incoming month bstack ds.b 1 ;incoming day / outgoing result xstack ds.w 1 ;incoming year ystack ds.w 1 ;just saved ;;;;;;;;;;;;;;;;;;;; code starts here ;;;;;;;;;;;;;;;;;;;;;; zeller pshy pshx pshb ;(*) accb will get modified psha ;save registers ;; allocate temp storage on the stack ldab #ssiz ;storage size alloc des ;reserve stack decb ;more? bne alloc ;yes do rest tsy ;stack -> y (points to temp storage) ldd #0 ;d=0 std tmp,y ;initialize accumulator ldab astack,y ;get month lo byte std mn,y ;store month (a=0) ldab bstack,y ;get day lo byte std dy,y ;store day (a=0) ldd xstack,y ;get year std yr,y ;store year (word) ;; this does "month 13 and 14" correction ldd mn,y ;get month cpd #2 ;jan or feb? bhi zel2 ;no addd #12 ;yes, add a year std mn,y ;store updated month ldd yr,y ;get year subd #1 ;correct year (yr=yr-1) std yr,y ;store updated year zel2 ldd mn,y ;m addd #1 ;(m+1) ldaa #26 ;26 mul ;d=(m+1)*26 ldx #10 ;10 idiv ;x=((m+1)*26)/10 xgdx ;x->d addd tmp,y ;do f1 std tmp,y ;store intermediate ldd yr,y ;year ldx #4 ;4 idiv ;x=(year/4) xgdx ;x->d addd tmp,y ;do f2 std tmp,y ;store intermediate ldd yr,y ;year ldx #100 ;100 idiv ;x=(year/100) xgdx ;x->d ldaa #6 ;a=6 mul ;d=6*(year/100) addd tmp,y ;do f3 std tmp,y ;store intermediate ldd yr,y ;year ldx #400 ;400 idiv ;x=(year/400) xgdx ;x->d addd tmp,y ;do f4 std tmp,y ;store intermediate ldd dy,y ;get day addd tmp,y ;add intermediates addd yr,y ;add year subd #1 ;-1 (make sunday=0) ldx #7 ;mod 7 idiv ;x=d/x, quotient to x, remainder to d stab bstack,y ;(*) store result, return in accb ;; deallocate storage on the stack ldab #ssiz ;storage size dealloc ins ;deallocate decb ;more? bne dealloc ;yes do rest ;; restore registers pula pulb ;(*) day of week was placed here pulx puly ;restore registers rts ;return with day of week in b ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; input (read) data from serial port ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; input ldaa scsr ;read status reg anda #%00100000 ;check rdrf flag beq input2 ;exit w/a=0 if no data ldaa scdr ;read serial data input2 rts ;return ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; output (write) data to serial port ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; output psha ;save a ldaa scsr ;read sci status register coma ;invert bits bita #%11000000 ;test tdre & tc pula ;restore a bne output ;sci busy, check again staa scdr ;send character rts ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; out string (print) string to serial port ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; outstrg ldaa 0,x ;get a char beq outs2 ;done bsr output ;send character out inx ;increment buffer ptr bra outstrg ;send next outs2 rts ;return ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; text messages for terminal ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; msg1 dc.b $0d,$0a dc.b 'ENTER TIME & DATE:' dc.b $0d,$0a hro equ *-prompt ;offset prompt dc.b 'HH ' ;hours prompt mio equ *-prompt dc.b 'MM ' ;minutes prompt sco equ *-prompt dc.b 'SS ' ;seconds prompt mno equ *-prompt dc.b 'MM ' ;month prompt dao equ *-prompt dc.b 'DD ' ;date prompt yro equ *-prompt dc.b 'YY' ;year prompt prlen equ *-prompt ;prompt length (for input limit) crlf dc.b $0d,$0a,0 msg2 dc.b $0d,$0a dc.b 'READBACK ',0 msg2s dc.b 'CORRECT!' dc.b $0d,$0a,0 msg2f dc.b 'FAILED!' dc.b $0d,$0a,0 msg3 dc.b $0d,$0a dc.b 'CANCELLED BY USER',0 msg4 dc.b $0d,$0a dc.b 'DATA OUT OF RANGE' dc.b $0d,$0a,0 ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; buffers & vars in 'hc11 sram ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; org $100 ;evbu ram buffer ds.b 32 ;incoming data buffer bufsiz equ *-buffer ;size of buffer curpos ds.b 1 ;cursor position clkbuf ds.b 8 ;data to be fed to clock verbuf ds.b 8 ;clock verify buffer end

IMayNeed · 06-09-2012, 03:24 AM

Thank you for the help everybody. I am copying this whole page and getting home. Today, I just got out of 2 finals so, I will rest probably, but Weekend, I will finish this calendar and the rest of the site (one transaction, one credit card, one comment forms).

I have to ask this too (after checking out books mostly -don't have internet at home-); I have a frame (row) at the top and when I make the window smaller, the text disappears. Is there any way to avoid that or with the right words, what are the ways to avoid that? I checked out the books I had, but either I am not getting it or I am having a hard time to get it or something else!

Thanks again.

felgall · 06-09-2012, 04:13 AM

Quote:

Originally Posted by Krupski

I do need parseInt because the algorithm depends on integer math and indeed fails if floating point numbers get involved.

but parseInt() in JavaScript doesn't convert the values to integers, it converts between number bases eg base 16 to base 10

Math.floor() is the JavaScript function to convert from a float to an integer.

Krupski · 06-09-2012, 04:44 AM

Quote:

Originally Posted by felgall

but parseInt() in JavaScript doesn't convert the values to integers, it converts between number bases eg base 16 to base 10

Math.floor() is the JavaScript function to convert from a float to an integer.

We are like "Rock'em-Sock'em Robots"... trying to knock off each other's block.

parseInt defaults to base 10 so it does the same thing as Math.floor.

As to which one is "better"... does it matter? Do you eat the cake first, or the frosting first? And does it matter either way?

felgall · 06-09-2012, 04:56 AM

Quote:

Originally Posted by Krupski

parseInt defaults to base 10 so it does the same thing as Math.floor.

parseInt doesn't always default to base 10 - sometimes it defaults to base 8.

The difference between using the function intended to convert to integer Math.floor(x) and one that does so as a side effect but which is actually intended for a different purpose parseInt(x,10) is the same difference as there is between driving a Ford to work or driving a Cesna to work - one is intended for that purpose and the other is intended to be used for something different.

Just watch out that you don't get your wings knocked off next time you drive your Cesna to work.

In particular parseInt should NEVER be used where dates are concerned because of the danger that it will treat numbers as base 8 instead of base 10 and so will fail to work on the 8th and ninth of each month as well as failing completely for August and September. I have lost count of the number of forum questions I have answered where this problem occurred because someone misused parseInt.

Anyway that code you posted with 15 lines in the function is about 13 lines longer than necessary as I showed in my following post where including the actual call to the function my solution used only 3 lines of code to do the same thing.