Use PHP to show page identified by URL parameters?

[dan-dan]

PHP Code:

$url = (isset ($_GET['url']) && file_exists($_GET['url'])) ? "files/" . strtolower($_GET['track']) : "http://example.com/404.html"; 


You're using both 'url' and 'track'. Is that the problem?

[Mooseman]

Originally Posted by dan-dan

You're using both 'url' and 'track'. Is that the problem?

The real parameter is 'track', I was changing it back for posting.

Do you see any errors with the code I posted? Thank you!

[dan-dan]

Think I made a boo boo with that one. I didn't include the full path to the file_exists() call.
Try:

PHP Code:

$url = (isset ($_GET['track']) && file_exists("files/" . $_GET['track'])) ? "files/" . strtolower($_GET['track']) : "http://example.com/404.html"; 


[Mooseman]

It works! The only thing left is that I am still having to make the parameter exampleFile.html, and not just exampleFile. Since all filenames will be html, there is no override needed. Thank you!

[dan-dan]

This should do it

PHP Code:

$url = (isset ($_GET['track']) && file_exists("files/".strtolower($_GET['track']).".html")) ? "files/".strtolower($_GET['track']).".html" : "http://example.com/404.html"; 


[Mooseman]

Works perfectly now! Thank you!

[dan-dan]

No worries