using data

[abrofunky]

This program execute but It is not coming how I wanted.

for example I want name and grade to be in the column and row have what I had enter.


name Grade
J 54
K 65

#include <iostream>
#include <string>

using namespace std;

    struct student
{

    string name;
    int grade;

};

 int main()
 {
     student people1;
     student people2;


     cout << "Please enter student name: ";
     cin >> people1.name;
     cout <<" Pleae enter student grade: ";
     cin >> people1.grade;

     cout << "Please enter student name: ";
     cin >> people2.name;
     cout <<" Pleae enter student grade: ";
     cin >> people2.grade;

     cout << "Name" << "          " << "Grade" << endl;

   cout << " people1.name " << "        " << " people1.grade " << endl;

   cout << " people2.name " << "        " << " people2.grade " << endl;

     cin.get();

 }

[Chocoholic_Jedi]

You don't want quotes around your calls to people1.name, people2.name, people1.grade and people2.grade in your print statements. That's why it's printing out "people1.name" "people1.grade", etc. instead of actually printing their name and grade. Just do

cout << people1.name;

instead when you're accessing a value when printing.

[nojtb]

Escape seqences

\a /*alert (bell)*/
\b /*backspace*/
\f /*formfeed*/
\n /*newline*/
\r /*carriage return*/
\t /*horizontal tab*/
\v /*vertical tab*/
\\ /*backslash*/
\? /*question mark*/
\' /*single quote*/
\" /*double quote*/
\000 /*octal number*/
\xhh /*hexadecimal number*/

cout << "Name" << "\t" << "Grade" << endl;
cout << people1.name << "\t" << people1.grade << endl;
cout << people2.name << "\t" << people2.grade << endl;

[abrofunky]

thanks alot that really helped out. Peace