Switch to return a name instead of number

[zelig]

Here is my dilemma.

I'm trying to get the "class name" to return instead of the number that is associated with it.

I wrote a switch so that each of the 16 cases would be associated with what the class name is.

However, how do I make it output into my statement?

Here is what I have so far:

PHP Code:

function getClassByNumber($x){
switch($x){
case 1: return "Alchemist";
case 2: return "Assassin";
case 3: return "Dark Arts";
case 4: return "Dark Paladin";
case 5: return "Entertainer";
case 6: return "Hunter";
case 7: return "Mage";
case 8: return "Monk";
case 9: return "Paladin";
case 10: return "Pirate";
case 11: return "Priest";
case 12: return "Psion";
case 13: return "Scholar";
case 14: return "Thief";
case 15: return "Warlock";
case 16: return "Warrior";
}
}

$class = getClassByNumber($username->class);

echo You are now a $class. 


Username is defined as seeking the table I want. Class is the field where the number is stored.

Thanks!

[mlseim]

What is happening now ... with the script you have?

[zelig]

I have a table in my database (users) that contains a field (class) that is comprised of numbers. I want to convert those numbers to class names (warrior, mage, etc.) and have it print out what class name that person is, rather than just "You are a 1."

Does that makes sense?

[mlseim]

example with a few names.
0=none ... since arrays start at zero (0) ...

$names=array("none", "Alchemist", "Assassin", "Dark Arts", "Dark Paladin");
echo "Name is: ".$names[$class];

[zelig]

Hmm... I got this error:

Warning: mysql_result() [function.mysql-result]: None not found in MySQL result index 615 in

Here is what I have.

PHP Code:

function getClassByNumber($x){
switch($x){
case 0: return "None";
case 1: return "Alchemist";
case 2: return "Assassin";
case 3: return "Dark Arts";
case 4: return "Dark Paladin";
case 5: return "Entertainer";
case 6: return "Hunter";
case 7: return "Mage";
case 8: return "Monk";
case 9: return "Paladin";
case 10: return "Pirate";
case 11: return "Priest";
case 12: return "Psion";
case 13: return "Scholar";
case 14: return "Thief";
case 15: return "Warlock";
case 16: return "Warrior";
}
}

$names=array("none", "Alchemist", "Assassin", "Dark Arts", "Dark Paladin", "Entertainer", "Hunter", "Mage", "Monk", "Paladin", "Pirate", "Priest", "Psion", "Scholar", "Thief", "Warlock", "Warrior");

$dString = "The $names $peepr known as $button<a href=main.php?username=$username&password=$password&action=look+at+$peeps[$i] $overlib>$thepeepname</a> is here$d<br>\n"; 


[mlseim]

That error must be from a different part of the script.
I see nothing in what you posted that indicates any MySQL functions or the $names array.