String to INT

[Gomez]

I am trying to convert a string to int value. Is there anyway to implement a if else statement in this so if the user inputs anything else besides an int . it would display an error. otherwise if the user inputs a string of int's it displays the int's.

	public static void main(String[] args) {
		
		System.out.println("Enter your string to be converted");
		Scanner Keyboard = new Scanner(System.in);
		
		 String S1 = Keyboard.next();
			
		Integer x = Integer.valueOf(S1);
		System.out.println("The Int is:" + "\n"+ S1 );
}
}

[oesxyl]

Originally Posted by Gomez

I am trying to convert a string to int value. Is there anyway to implement a if else statement in this so if the user inputs anything else besides an int . it would display an error. otherwise if the user inputs a string of int's it displays the int's.

	public static void main(String[] args) {
		
		System.out.println("Enter your string to be converted");
		Scanner Keyboard = new Scanner(System.in);
		
		 String S1 = Keyboard.next();
			
		Integer x = Integer.valueOf(S1);
		System.out.println("The Int is:" + "\n"+ S1 );
}
}

java.util.regex, Pattern and Matcher?

best regards

[Fou-Lu]

pattern matching will help you to tell if it is a number, but still won't cast it so you'll still need the parse if you want to treat it as a number.
Just try/catch it instead, its much simpler. Integer.parseint will throw a NumberFormatException if it can't be parsed:

PHP Code:

try
{
   Integer x = Integer.valueOf(S1);
   System.out.println("The int is: " + x);
}
catch (NumberFormatException ex)
{
    System.out.println(S1 + " is not a number.");
}