php date format

santille · 12-09-2010, 02:11 PM

Hello,

Please any help about that.
Here is the code :

Code:

for($m = 0;$m <= 0; $m++)
{
$now = date ("Y-m-d", mktime (0,0,0,date("m"),date("d")+$m,date("Y")));
echo "<input type=\"hidden\" name=\"open_date\" value=\"" . $now . "\">";
}

It inserts the actual date in YYYY-MM-DD.
The field "open_date" in the MYSQL table is type "date".
Could you please give the exact modification to give to this code to have DD-MM-YYYY format cause for the moment always 0000-00-00 result...

Thanks a lot,

seb

DataTalk · 12-09-2010, 03:25 PM

Quote:

Originally Posted by santille

Hello,

Please any help about that.
Here is the code :

Code:

for($m = 0;$m <= 0; $m++)
{
$now = date ("Y-m-d", mktime (0,0,0,date("m"),date("d")+$m,date("Y")));
echo "<input type=\"hidden\" name=\"open_date\" value=\"" . $now . "\">";
}

It inserts the actual date in YYYY-MM-DD.
The field "open_date" in the MYSQL table is type "date".
Could you please give the exact modification to give to this code to have DD-MM-YYYY format cause for the moment always 0000-00-00 result...

Thanks a lot,

seb

just change this to "d-m-y"

santille · 12-09-2010, 03:45 PM

Thank you for your answer.
No way with this task : that's the first thing I tried.

DataTalk · 12-09-2010, 03:52 PM

I just tyied it the output was 09-12-2010 instead of 2010-12-09

Code:

<?php        
for($m = 0;$m <= 0; $m++)
{
$now = date ("d-m-Y", mktime (0,0,0,date("m"),date("d")+$m,date("Y")));
echo "<input type='text' name='open_date' value='$now'>";
} 
?>

santille · 12-09-2010, 04:06 PM

Could you tell me exactly how did you test to obtain this result?
It does not return that for me...