Javascript validation problem

factory! · 03-01-2010, 05:58 PM

I have an issue with a form I am creating, I have many check boxs where at least one of the 2 needs to be selected and the final one has to be selected for the submit button to become active

Code:

<form id="form1" action="#" method="post">

One <input type="checkbox" name="value1" onMouseDown='submit_form()'/>
Two<input type="checkbox" name="value2" onMouseDown='submit_form()'/>
//atleast 1 of these 2 has to be selected

Three<input type="checkbox" name="value3" onMouseDown='submit_form()'/>
//this 1 has to be selected

<input type="submit" name="submit" value="submit" id="submit" disabled="disabled"/>

this is the javascript I have atm to do this

Code:

function submit_form(){
	if (form1.value1.checked == false || form1.value2.checked == false) {
		document.getElementById(submit);
		orderForm.submit.disabled=false;
	}
}

i cant seem to get this to work, forgetting about the 3rd checkbox for now

any help would be greatly appreciated!

Philip M · 03-01-2010, 07:47 PM

There ain't no such thing as onMouseDown in relation to a checkbox. onclick perhaps?

if (form1.value1.checked == false && form1.value2.checked == false) {
alert ("You must check one of the two checkboxes to proceed");
return false;
}
if (form1.value3.checked == false) {
alert ("You must check box 3 before you can proceed");
return false;
}

It is your responsibility to die() if necessary….. - PHP Manual

factory! · 03-01-2010, 08:09 PM

thankyou for that, helped solve the problem!