In your example, jquery can't get the IDs of the rows because you haven't provided them. If you want to toggle images per cell (td), you need to provide jquery with the information necessary to locate each.
Easy way: set IDs on the TR tags and classes on the TD tags.
Code:
<table>
<tr id="row1">
<td class="col1">Some title</td><td class="col2">Some description</td><td class="col3">Some name</td>
</tr>
<tr id="row2">
<td class="col1">Some title2</td><td class="col2">Some description2</td><td class="col3">Some name2</td>
</tr>
<tr id="row3">
<td class="col1">Some title3</td><td class="col2">Some description3</td><td class="col3">Some name3</td>
</tr>
</table>
You could use IDs instead of classes on each TD, but this version uses fewer names so it's a little easier to understand. Also, this version is easier to read in English (go to row 2 column 3) which makes it easier to write the jquery for each location. For example, you can access row 2 column 3 with
$('#row2 td.col3').hover(myHoverFunction);.
If you really mean that you only want a different image for each
row, then it can be much simpler. But I assume you meant that you want a different image for each
cell.