Hi all,
I have a piece of code which echo's out a website URL and is linked, however its displaying the URL as:
http://www.mydomain.co.uk/directory/www.externalurl.com
whereas I want to just echo the external url...
The code is:
PHP Code:
<?php
$query = "SELECT * FROM teachingagencies_directory WHERE agencyname LIKE '%$agencyname%' AND region LIKE '%$region%' AND address LIKE '%$city%' AND address LIKE '%$postcode%' $limit";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array ($result)) {
$i++;
if ($i & 1) {
echo "
<div class='color1'>
<a href='agencydetails.php?Name=" . $row['agencyname'] . "'>" . $row['agencyname'] . "</a>
<br/>
<br/>
<span class='bold'>Address:</span> <span class='normalfont'>" . $row['address'] . "</span>
<br/>
<span class='bold'>Telephone:</span> <span class='normalfont'>" . $row['telephone'] . "</span>
<br/>
<span class='bold'>Website:</span> <span class='normalfont'><a href='" . $row['website'] . "'>" . $row['website'] . "</a></span>
<br/>
<br/>
</div>";
}
else {
echo "
<div class='color2'>
<a href='agencydetails.php?Name=" . $row['agencyname'] . "'>" . $row['agencyname'] . "</a>
<br/>
<br/>
<span class='bold'>Address:</span> <span class='normalfont'>" . $row['address'] . "</span>
<br/>
<span class='bold'>Telephone:</span> <span class='normalfont'>" . $row['telephone'] . "</span>
<br/>
<span class='bold'>Website:</span> <span class='normalfont'><a href='" . $row['website'] . "'>" . $row['website'] . "</a></span>
<br/>
<br/>
</div>";
}
}
?>
The $row['website'] references a field in the database that contains the url in question - i.e.
www.codingforums.com.
Can anyone see why this maybe happening???