how to generate a thumbnail?

[FIA2008]

How can I generate a thumbnail with script?

PHP Code:

<?php
/* Start Verwerking */
if($_SERVER['REQUEST_METHOD'] == 'POST'){
    $ext            = $_FILES['type'];
    $file_name        = md5(rand(0, 1000).'-'.time()).$ext.".jpg";
    $target_path    = "../photo/".$_POST['album']."/".$file_name;
    $ar        = array();
    $ar[0]    = 'image/jpeg';
    
    $title            = mysql_real_escape_string($_POST['title']);
    $description    = mysql_real_escape_string($_POST['description']);
    $album            = mysql_real_escape_string($_POST['album']);

    if(isset($_POST['send'])){
        $fouten = array();
        if (empty($_POST['title'])){
            $fouten[] = "Geen naam ingevuld!";
        }
        if(empty($_POST['description'])){
            $fouten[] = "Geen beschrijving ingevuld!";
        }
        if(empty($_POST['album'])){
            $fouten[] = "Geen album opgegeven!";
        }
        if(empty($_FILES['file']['name'])){
            $fouten[] = "Geen foto geselecteerd!";
        }
        if(!in_array($_FILES['file']['type'],$ar)){
            $fouten[] = "Verkeerd bestandstype!";
        }
        $counter = count($fouten);
        if($counter > 0){
        echo "    <font color='#FF0000'>
                    <ol>
                        <font color='#000000'>De volgende velden zijn niet correct ingevuld:</font>
                        <li>".join("</li>
                        <li>", $fouten)."</li>
                    </ol>
                </font>";
        }
    }
    if($counter == 0){
        if(in_array($_FILES['file']['type'],$ar)){            
            $sql = "INSERT INTO photo_photo(id, title, description, album, file)
            VALUES ('','".$title."', '".$description."', '".$album."', '".$file_name."')";
            mysql_query($sql);
            move_uploaded_file($_FILES['file']['tmp_name'], $target_path);
            echo "<br>Foto is succesvol ge&uuml;pload en in het album geplaatst.<br>";
        }
    }
}
/* Einde Verwerking */
$photo    = "SELECT * FROM photo_photo";
$photo    = mysql_query($photo);
$album    = "SELECT * FROM photo_album ORDER BY id";
$album    = mysql_query($album);
?>
<form name="photo_add" method="post" action="<?php $_SERVER['PHP_SELF'] ?>" enctype="multipart/form-data">
<table>
    <tr>
        <td>Naam</td>
        <td><input type="text" name="title" size="45" /></td>
    </tr>
    <tr>
        <td>Beschrijving</td>
        <td><textarea name="description" cols="34"></textarea></td>
    </tr>
    <tr>
        <td>Album</td>
        <td>
            <select name="album">
            <?php
            while($album_rij = mysql_fetch_array($album)){
                ?>
                <option value="<?php echo $album_rij[0] ?>"><?php echo $album_rij[1] ?></option>
                <?php
            }
            ?>
            </select>
        </td>
    </tr>
    <tr>
        <td>Selecteer een foto</td>
        <td><input type="file" name="file" size="45" /></td>
    </tr>
    <tr>
        <td></td>
        <td><input type="submit" value="Foto toevoegen" name="send" /></td>
    </tr>
</table>
</form>

FIA2008

[thales.jacobi]

$big_file=$_FILES['file']['tmp_name'];
$new_file='/tmp/thumbnail.jpg';

copy($big_file, $new_file);

$thumb_width=50;
$thumb_height=35;

$thumb = imagecreatetruecolor($thumb_width,$thumb_height);
$source = imagecreatefromjpeg($big_file);
imagecopyresized($thumb,$source,0,0,50,35,$thumb_width,$thumb_height,188,188);

imagejpeg($thumb,$new_file);