How to pass the value of the input box to other page when click the button

[che_anj]

Hello anybody could give me idea how to pass the value of input box to other page when clicking the button..

I have a Page that will search according to what category you choose, and the query code execute to other page...

below is my code...

PHP Code:

    $searchcategory=array("Client","Jobs","Candidates");
    $searchval=array("employer_id","vacancy_id","candidate_id");
<form name="quicksearch" method="post">
<tr><td>Keywords</td>
<td><input type="text" name="qsearch" class="inputbox"></td>
</tr>
<tr>
                <td >Category</td>
                <td>
                    <select name="find" class="small">';
                        $index=0;
                        foreach($searchcategory as $sc)
                        {
                            if($searchval[$index]==$find)
                echo '<option value="'.$searchval[$index].'" selected>'.$sc.'</option>';
                        else
                echo '<option value="'.$searchval[$index].'">'.$sc.'</option>';
                        $index++;
                        
                        }
                echo '</select></td>
                </tr>    

<tr><td>
    <input type="submit" name="search" value="Search">
       </td>
</tr>
</form> 


when clicking the search button the result must display to other page

the filename of the said page is client_list.php but since all pages are under the menu.php, therefore the url looks like this http://www.mysite.com/menu.php?click...ist.php&menu=1

tnx.. hope u get it..

[Inigoesdr]

You need to specify the next page in action="page.php" inside of the <form> tag.

[che_anj]

I dont think it work because the said page was being include in the menu.php where the form for search is located...

the url must look like below..
http://www.mysite.com/menu.php?page.php&menu=1

if i will simply put the action="page.php"

it look like this
http://www.mysite.com/page.php which is not what i mean because the page.php is being called in the menu.php like this require $_GET['click'];

[rafiki]

you need to send it to menu.php then form data will be attached to menu.php like so
http://www.mysite.com/page.php?menu=...hing=something

[Inigoesdr]

Originally Posted by che_anj

I dont think it work because the said page was being include in the menu.php where the form for search is located...

the url must look like below..
http://www.mysite.com/menu.php?page.php&menu=1

if i will simply put the action="page.php"

it look like this
http://www.mysite.com/page.php which is not what i mean because the page.php is being called in the menu.php like this require $_GET['click'];

If you want to send the variables in the URL and use $_GET to retrieve them then you need to change your form method to: method="get".

[rafiki]

Originally Posted by Inigoesdr

If you want to send the variables in the URL and use $_GET to retrieve them then you need to change your form method to: method="get".

didnt catch that sorry