ajax script not working :( plz help

[sonic656]

My code:

JAVASCRIPT PART:

function test() {
	$.ajax({
		url: '../ajax/test.php',
	}).done(function(data) { 
		return data;
	});
}
alert(test());

PHP PART:

<?php
	echo "Hello, world!";
?>

What I'm doing wrong ? :/



PS: Im loaing jQuery mini 1.8 from jquery website.

[WolfShade]

Do you mean to go back one directory/folder and then access a sub-folder called "ajax"?

If the URL is the only argument, remove the comma after test.php',

[devnull69]

You tried to return something from your "outer" function test(), but instead you only return something from the "inner" anonymous closure function.

General rule: Every action that depends on the outcome of an asynchronous method must be run inside the callback of that method or must be called from that callback. Returning anything doesn't make any sense because at the time the callback is run, the outer function has already finished.

[sonic656]

Soo.....How can I edit it, so it will work?

PS: removing that comma after test.php' did not affect anything

[devnull69]

Whatever you want to do with "data", just do it inside the .done() method

[sonic656]

and what with the return code? how can I return the data?

[devnull69]

You didn't get me ... technically you can return something from each and every function, but semantically it doesn't make any sense to return something from the callback of an asynchronous method because it will end up "in thin air". The calling method has long finished before the callback is executed so you cannot return anything from it.

So:

General rule: Every action that depends on the outcome of an asynchronous method must be run inside the callback of that method or must be called from that callback. Returning anything doesn't make any sense because at the time the callback is run, the outer function has already finished.

[WolfShade]

In other words, I don't think you can "return" anything for the alert.. now you should be able to put the alert inside the callback function. Or, alternatively, create a div, give it an id, and use .html() to place the data in it.