Using token string in if statement

[epheterson]

I have a scanner running, which correctly retrieves tokens how I want them (using white space as the delimiter). It prints out the tokens, as I'd like, to the screen, but when I run an if(token == "string"), using the exact output from the terminal, the if statement never runs.

		while(s.hasNext())
		{
			String token = s.next();
			System.out.println(token);
			
			if(token == "insert")
			{
					// call insert command
					System.out.println("Inserting");
			}
			else if(token == "process")
			{
					// call process command
					System.out.println("Processing…");
			}
			else if(token == "count")
			{
					// call count command
					System.out.println("Counting…");
			}
			else if(token == "list")
			{
					// call list command
					System.out.println("Listing…");
			}
			else if(token == "priority")
			{
					// call priority command
					System.out.println("Prioritizing…");
			}
			else
			{
					System.out.println("Chuck Norris can unscrable an egg.");
			}
					

			
		}

The output:
insert
Chuck Norris can unscrable an egg.
Smith,
Chuck Norris can unscrable an egg.
John
Chuck Norris can unscrable an egg.
1
Chuck Norris can unscrable an egg.
15
Chuck Norris can unscrable an egg.
insert
Chuck Norris can unscrable an egg.
Oldman,
Chuck Norris can unscrable an egg.
Richard
Chuck Norris can unscrable an egg....


Any ideas what I can change?

[Fou-Lu]

Token is a string object, you cannot compare using ==. == in this context will match the address for the variable.
Instead, use token.equals("insert") for a comparison.

[epheterson]

Thank you! Works like a charm, I guess I'm too used to PHP

[Fou-Lu]

Yep, you can alter that if you code php as if it were more typestrong:

PHP Code:

if (0 === strcmp($myVar, 'search'))
{
    // Indicates they are equal
} 


Us PHP developers are just spoiled with the loose comparisons