AJAX activation on multipul drop dorwns

Phil Jackson · 09-13-2009, 12:37 PM

Hi i have the following code:

Code:

<script type="text/javascript">
jQuery(document).ready(hostCalc);
function hostCalc(){
	$("SELECT").change(function(){
		var diskSpace = jQuery("#diskSpace :selected").text();
		var bandwidth = jQuery('#bandwidth :selected').text();
		var subDomains = jQuery('#subDomains :selected').text();
		var additionalFTP = jQuery('#additionalFTP :selected').text();
		var mysqlDatabases = jQuery('#mysqlDatabases :selected').text();
		var emailForwarding = jQuery('#emailForwarding :selected').text();
		var AutoResponders = jQuery('#autoResponders :selected').text();
		var emailDistributionLists = jQuery('#emailDistributionLists :selected').text();
		var mailBoxes = jQuery('#mailBoxes :selected').text();
		var operatingSystem = jQuery('#operatingSystem :selected').text();
		var oneClick = jQuery('#oneClick :selected').text();
		
		$.ajax({
			type: "GET", 
			data: 'discSpace=' + discSpace + '&bandwidth=' + bandwidth + '&subDomains=' + subDomains + '&additionalFTP=' + additionalFTP + '&mysqlDatabases=' + mysqlDatabases + '&emailForwarding=' + emailForwarding + '&AutoResponders=' + AutoResponders + '&emailDistributionLists=' + emailDistributionLists + '&mailBoxes=' + mailBoxes + '&operatingSystem=' + operatingSystem + '&oneClick=' + oneClick, 
			url: 'hostCalc.php', 
			cache: false, 
			timeout: 1000, 
			error: function(){
			},
			success: 
			function(html){
				$("#cost").html(html);
			}
		});
	});
}
</script>

the hostCalc.php simply :

PHP Code:


			
<?php

echo "foo";

?>

i seem to get no response back from the php script. Anyone know why?

A1ien51 · 09-14-2009, 03:34 AM

what does fiddler or firebug say comes back?

Eric

A1ien51 · 09-14-2009, 03:36 AM

Instead of getting every single form element, you can use seralize.

Code:

$("#formId").serialize();

Eric