Go Back   CodingForums.com > :: Client side development > JavaScript programming > Ajax and Design

Before you post, read our: Rules & Posting Guidelines

Reply
 
Thread Tools Rate Thread
Enjoy an ad free experience by logging in. Not a member yet? Register.
Old 04-24-2009, 10:23 AM   PM User | #1
cherubrock74
New to the CF scene

 
Join Date: Apr 2009
Posts: 2
Thanks: 0
Thanked 0 Times in 0 Posts
cherubrock74 is an unknown quantity at this point
drop down menu issue

Hi all
I have a set of three drop down menu that I would like to duplicate. I would like to create other sets of three menus but I cannot get them to be independent from the previous set. I believe it has to do with the JS that controls the selections...
also I would like to make the selections without the page refreshing because I will use the drop down menus in a form and the user will lose text that was eventually input before the selection...is there a way to accomplish that using ajax?

Not sure if this is the right place to post, if not I apologize and ask the mod to please move the thread to the appropriate forum
here is my working code, so far...(this include only 1 set of 3 drop down menus)

Code:
<html>

<head>
<title>Demo of Three Multiple drop down list box from plus2net</title>

<script language=JavaScript>
function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value; 
self.location='form2.php?cat=' + val ;
}
function reload3(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value; 
var val2=form.subcat.options[form.subcat.options.selectedIndex].value; 

self.location='form2.php?cat=' + val + '&cat3=' + val2 ;
}

</script>


<?php

require "config.php";
///////// Getting the data from Mysql table for first list box//////////
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category"); 
///////////// End of query for first list box////////////

/////// for second drop down list we will check if category is selected else we will display all the subcategory///// 
$cat=$HTTP_GET_VARS['cat']; // This line is added to take care if your global variable is off
if(isset($cat) and strlen($cat) > 0){
$quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory where cat_id=$cat order by subcategory"); 
}else{$quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory order by subcategory"); } 
////////// end of query for second subcategory drop down list box ///////////////////////////

/////// for Third drop down list we will check if sub category is selected else we will display all the subcategory3///// 
$cat3=$HTTP_GET_VARS['cat3']; // This line is added to take care if your global variable is off
if(isset($cat3) and strlen($cat3) > 0){
$quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 where subcat_id=$cat3 order by subcat2"); 
}else{$quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 order by subcat2"); } 
////////// end of query for third subcategory drop down list box ///////////////////////////

echo "<form method=post name=f1 action='send.php'>";

//////////        Starting of first drop downlist /////////
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($noticia2 = mysql_fetch_array($quer2)) { 
if($noticia2['cat_id']==@$cat){echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";}
else{echo  "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";}
}
echo "</select>";
//////////////////  This will end the first drop down list ///////////

//////////        Starting of second drop downlist /////////
echo "<select name='subcat' onchange=\"reload3(this.form)\"><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) { 
if($noticia['subcat_id']==@$cat3){echo "<option selected value='$noticia[subcat_id]'>$noticia[subcategory]</option>"."<BR>";}
else{echo  "<option value='$noticia[subcat_id]'>$noticia[subcategory]</option>";}
}
echo "</select>";
//////////////////  This will end the second drop down list ///////////


//////////        Starting of third drop downlist /////////
echo "<select name='subcat3' ><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer3)) { 
echo  "<option value='$noticia[subcat2]'>$noticia[subcat2]</option>";
}
echo "</select>";
//////////////////  This will end the third drop down list ///////////

?>
cherubrock74 is offline   Reply With Quote
Reply

Bookmarks

Jump To Top of Thread


Thread Tools
Rate This Thread
Rate This Thread:

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT +1. The time now is 10:26 PM.


Advertisement
Log in to turn off these ads.