while y/n

[Patrik116]

PHP Code:

    import java.util.Random;
    import java.util.Scanner;
    class indexerad_variable
    {
    public static void main(String[] args)
    {
     
        Random generator = new Random();
        Scanner scan = new Scanner(System.in);
         
        int Tries=0;
        int number = generator.nextInt(100) + 1;
        String igen;
     
        while(true)
        {
        System.out.print("\nNumber 1 - 100: ");
        Tries++;
        int guess = scan.nextInt();
         
        if(guess < number)
        {
        System.out.println("to low");
        }
         
        if(guess > number)
        {
        System.out.println("to high");
        }
         
        if(guess == number)
        {
        System.out.println("Right you have tried "+Tries+" ");
        {
        }
         System.out.print("\nPlay again y/n: ");
         igen = scan.next();
         if (igen.equalsIgnoreCase("N"))
         break;
        }
        }
        }
        } 


The program works but when i press y it will com back to the last game. and if i type in a break under tries its only go 1 turn in the game. can anyone tell me what i need to do to fix this game?

[alykins]

you never call this again

int number = generator.nextInt(100) + 1;

so the number is the same

and if i type in a break under tries its only go 1 turn in the game.

I don't understand what you are trying to do or are saying... you mean

Tries++;
break;

that will break on "break;"
confused as to question or purpose....
I would do two loops...

bool GameDone=false;
bool CorrectInt=false;
while(!GameDone)
{
  initialize all your variables...
  while(!CorrectInt)
  {
   code for game
   on correct int guess set CorrectInt = true;
   }
   Ask if want to play again
   on n set GameDone = true;
}