To binary translation

[zverys36]

How can I translate multiple random numbers into binary? I know that to translate one number to binary, this declaration is needed: String myString = Integer.toBinaryString(a number), but what if the number is random?

[Fou-Lu]

I don't understand your question. Integer.toBinaryString will work on any integer provided for it; it doesn't matter if you type in a Integer.toBinaryString(5); or an Integer.toBinaryString(myInt).
Can you be more specific on the question?

[zverys36]

Originally Posted by Fou-Lu

I don't understand your question. Integer.toBinaryString will work on any integer provided for it; it doesn't matter if you type in a Integer.toBinaryString(5); or an Integer.toBinaryString(myInt).
Can you be more specific on the question?

OK, so I have to read a few numbers using Java. The numbers are not hard-coded - they depend on whichever text file I choose to read. I need to take those numbers that I read and translate them into binary. For example, if a text file contains the numbers:

PHP Code:

2
a string
5 


I want the numbers to be read and translated into binary (skipping the string).

PHP Code:

10
a string
101 


[Fou-Lu]

Originally Posted by zverys36

OK, so I have to read a few numbers using Java. The numbers are not hard-coded - they depend on whichever text file I choose to read. I need to take those numbers that I read and translate them into binary. For example, if a text file contains the numbers:

PHP Code:

2
a string
5 


I want the numbers to be read and translated into binary (skipping the string).

PHP Code:

10
a string
101 


Gotcha.
The easiest way would be to read the data in as a string, parse it as an integer and display it. Using a try/catch would suit for this.

PHP Code:

BufferedReader br;
try
{
    br  = new BufferedReader(new Filereader("yourfile.txt"));
    String sLine = null;
    while (null != (sLine = br.readLine()))
    {
        String sDisplay = "";
        try
        {
            sDisplay = Integer.toBinaryString(Integer.parseInt(sLine).intValue());
        }
        catch (NumberFormatException ex)
        {
            sDisplay = sLine;
        }
        System.out.println("Line: " + sDisplay);
    }
}
catch (IOException ex)
{
    System.out.println("Failed to open file.");
}
finally
{
    try
    {
        br.close();
    }
    catch (Exception ex)
    {
    }
} 


Untested, but something like that should work.

[zverys36]

Originally Posted by Fou-Lu

Gotcha.
The easiest way would be to read the data in as a string, parse it as an integer and display it. Using a try/catch would suit for this.

PHP Code:

BufferedReader br;
try
{
    br  = new BufferedReader(new Filereader("yourfile.txt"));
    String sLine = null;
    while (null != (sLine = br.readLine()))
    {
        String sDisplay = "";
        try
        {
            sDisplay = Integer.toBinaryString(Integer.parseInt(sLine).intValue());
        }
        catch (NumberFormatException ex)
        {
            sDisplay = sLine;
        }
        System.out.println("Line: " + sDisplay);
    }
}
catch (IOException ex)
{
    System.out.println("Failed to open file.");
}
finally
{
    try
    {
        br.close();
    }
    catch (Exception ex)
    {
    }
} 


Untested, but something like that should work.

Thanks, it worked!