Regular Expression Solution

[styks1987]

I am pulling a URL from the address bar and parse it down until I get this
(The 'sortby' changes so I have to detect it dynamically)

sortby=industry&tuition=true

OR

sortby=industry

I want this to return

tuition=true

OR

Nothing

This is the regex I am currently using. It works for one but not the other.
/(^sortby=)[A-Za-z|\_|\+|\W]{1,}&/

Thank you for you time!

Michael

[Keleth]

Can sortby be anything but letters? If not

/^sortby=[a-z]+&?/

You don't need sortby= to be grouped, unless you're trying to capture it, but as its static, that serves no purpose. I think in your range, you were trying to add in A-Z or a-z or underscore or plus or word... that's not really necessary. First will you ever have a non-letter? If not, a-z is fine, then the i at the end for case insensitive. Finally, {1,} is the same as +. So use +. What you forgot is your second example doesn't have the &, but sometimes it might be there. So ? for 0 or 1.

[Keleth]

Can sortby be anything but letters? If not

/^sortby=[a-z]+&?/

You don't need sortby= to be grouped, unless you're trying to capture it, but as its static, that serves no purpose. I think in your range, you were trying to add in A-Z or a-z or underscore or plus or word... that's not really necessary. First will you ever have a non-letter? If not, a-z is fine, then the i at the end for case insensitive. Finally, {1,} is the same as +. So use +. What you forgot is your second example doesn't have the &, but sometimes it might be there. So ? for 0 or 1.