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Old Pedant · 01-20-2013, 09:56 PM

Array.push() is *NOT* a push-down stack.

It does exactly what you are seeing.

Basically if you do this:

Code:

var ary = [ ];
ary.push("apple");
ary.push("banana");
ary.push("coleslaw");

you get exactly the same result as if you had done

Code:

var ary = [ ];
ary[0] = "apple";
ary[1] = "banana";
ary[2] = "coleslaw";

which is the same you would get if you did

Code:

var ary = ["apple","banana","coleslaw"];

You can argue that the push( ) method of Array is misnamed. But it's way too late to change it now. It is what it is.

01-20-2013, 09:56 PM	PM User \| #2
Old Pedant Supreme Master coder! Join Date: Feb 2009 Posts: 23,187 Thanks: 59 Thanked 3,995 Times in 3,964 Posts	Array.push() is NOT a push-down stack. It does exactly what you are seeing. Basically if you do this: Code: var ary = [ ]; ary.push("apple"); ary.push("banana"); ary.push("coleslaw"); you get exactly the same result as if you had done Code: var ary = [ ]; ary[0] = "apple"; ary[1] = "banana"; ary[2] = "coleslaw"; which is the same you would get if you did Code: var ary = ["apple","banana","coleslaw"]; You can argue that the push( ) method of Array is misnamed. But it's way too late to change it now. It is what it is. __________________ An optimist sees the glass as half full. A pessimist sees the glass as half empty. A realist drinks it no matter how much there is.