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LearningCoder · 01-05-2013, 11:25 PM

It's echo'ing that because you are echo'ing the STRING mysql_error() rather than the actual return value of that function.

Try this:

PHP Code:


			
die("Error: ".mysql_error());

Hope it helps,

Kind regards,

LC.

01-05-2013, 11:25 PM	PM User \| #2
LearningCoder Regular Coder Join Date: Jan 2011 Location: The Pleiades Posts: 849 Thanks: 67 Thanked 28 Times in 28 Posts	It's echo'ing that because you are echo'ing the STRING mysql_error() rather than the actual return value of that function. Try this: PHP Code: `die("Error: ".mysql_error());` Hope it helps, Kind regards, LC. __________________ My Website: http://www.labtec.0fees.net/Gardenab...ved/?page=home Last edited by LearningCoder; 01-05-2013 at 11:42 PM..