Thread: Problem array, if! View Single Post
 12-05-2012, 01:20 PM PM User | #4 triko New Coder   Join Date: Oct 2012 Location: Italy Posts: 72 Thanks: 3 Thanked 0 Times in 0 Posts OK! as usual I haven't explained... I have the problem of the game roulette... When click start, put out one number random from 0 to 36 Code: var ball = Math.floor(Math.random()*36); before I have all my bets, example corners, split, red or black ecc... My problem born for corner, split, column, dozen ecc... Because I have all array of the possible combination, example columns: Code: var col1 = [1, 4, 7, 10, 13, 16, 19, 22, 25, 28, 31, 34]; var col2 = [2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35]; var col3 = [3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36]; Ok now in my css part I selected col1 and start the game... ball = 16; Now I don't know how tell that the number 16 is into col1! Other example is for split, there are so many, from split1 to split60: Code: var split1 = [0, 1]; var split2 = [0, 2]; var split3 = [0, 3]; var split4 = [1, 2]; var split5 = [2, 3]; var split6 = [1, 4]; var split7 = [2, 5]; var split8 ........... ecc Here have more combination possible and I don't know how to say if the ball = 0, if split 1 or 2 or 3!