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Old Pedant · 12-04-2012, 08:38 PM

If you use the keyword var *INSIDE* of a function, then all variables thus defined are accessible *ONLY* in that function.

When you return a value from a function, that return value WILL BE IGNORED unless it is assigned to a variable by the caller or used in some expression by the caller.

So, just for example, when you did

Code:

getvolume(length, width, height);

that call was useless. Because the function declared the variable v inside itself and so it is invisible outside the function *AND* you then ignored the value returned by the function.

A reasonable thing to do would have been something like

Code:

var volume = getvolume(length, width, height);

12-04-2012, 08:38 PM	PM User \| #9
Old Pedant Supreme Master coder! Join Date: Feb 2009 Posts: 23,248 Thanks: 59 Thanked 3,999 Times in 3,968 Posts	If you use the keyword var INSIDE of a function, then all variables thus defined are accessible ONLY in that function. When you return a value from a function, that return value WILL BE IGNORED unless it is assigned to a variable by the caller or used in some expression by the caller. So, just for example, when you did Code: getvolume(length, width, height); that call was useless. Because the function declared the variable v inside itself and so it is invisible outside the function AND you then ignored the value returned by the function. A reasonable thing to do would have been something like Code: var volume = getvolume(length, width, height); __________________ An optimist sees the glass as half full. A pessimist sees the glass as half empty. A realist drinks it no matter how much there is.