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 11-15-2012, 04:54 PM PM User | #30 Fou-Lu God Emperor     Join Date: Sep 2002 Location: Saskatoon, Saskatchewan Posts: 16,606 Thanks: 4 Thanked 2,598 Times in 2,567 Posts Start times at this point is irrelevant. Once you get the array of data you need split up properly, you can schedule time as you need based on ordered array. You'll need to have a full example. With 12 teams, 60 games is insufficient for every team to play every other team (you need 66 games for that). These are where your rules cannot be calculated mathematically. 8 teams require 28, 9 teams require 36, 10 45, 11 55, 12 66. Coming up with the combinations is the easy part. That's a simple: PHP Code: ``` function teamPlayCombinations(array \$aTeams){    \$aResult = array();    \$iTeams = count(\$aTeams);    for (\$i = 0; \$i < \$iTeams; ++\$i)    {        for (\$j = \$iTeams - 1; \$j > \$i; --\$j)        {            \$aResult[] = array(\$aTeams[\$i], \$aTeams[\$j]);        }    }    return \$aResult;}  ``` That would give all the possible combinations where order is not important (1 plays 2 is the same as 2 plays 1). But this is absolutely useless to you if at 8 @ 40 games gives you 12 too many, and 12 @ 60 games gives you 6 short. Scheduling so one team only plays once per week isn't a super easy task, but that just takes some conditional checking to see if they are scheduled to play already. But like I've been saying, until you specifically resolve your ruleset to dictate how you apply repeated plays (in the case of 8 @ 40) or whom doesn't play (in the case of 12 @ 60), then you cannot properly populate this data.