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Gomez

03-20-2011 02:47 AM

String to INT

I am trying to convert a string to int value. Is there anyway to implement a if else statement in this so if the user inputs anything else besides an int . it would display an error. otherwise if the user inputs a string of int's it displays the int's.

Code:

        public static void main(String[] args) {

                

                System.out.println("Enter your string to be converted");

                Scanner Keyboard = new Scanner(System.in);

                

                 String S1 = Keyboard.next();

                        

                Integer x = Integer.valueOf(S1);

                System.out.println("The Int is:" + "\n"+ S1 );

}

}

oesxyl

03-20-2011 02:54 AM

Quote:

Originally Posted by Gomez (Post 1067626)

Code:

        public static void main(String[] args) {

                

                System.out.println("Enter your string to be converted");

                Scanner Keyboard = new Scanner(System.in);

                

                 String S1 = Keyboard.next();

                        

                Integer x = Integer.valueOf(S1);

                System.out.println("The Int is:" + "\n"+ S1 );

}

}

java.util.regex, Pattern and Matcher?

best regards

Fou-Lu

03-20-2011 02:44 PM

pattern matching will help you to tell if it is a number, but still won't cast it so you'll still need the parse if you want to treat it as a number.
Just try/catch it instead, its much simpler. Integer.parseint will throw a NumberFormatException if it can't be parsed:

PHP Code:


		
			
try
{
   Integer x = Integer.valueOf(S1);
   System.out.println("The int is: " + x);
}
catch (NumberFormatException ex)
{
    System.out.println(S1 + " is not a number.");
}

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