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Thread: issues with using form in php
02-25-2008, 08:53 AM #1
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- Sep 2007
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issues with using form in php
i have 3 pages page1.php page2.php and page3.php
in page1.php user fills a registration form in page2.php the user can review what they have entered and make any changes and
page3.php displays a message that the registration has been completed.
have written works fine and does all the validation as the form elements in page1.php are written as
<input type="text" name=""> <input type="radio" name=""> ...
in page2.php i am displaying these form elements using php so that user can preview what they have entered and make changes
instead of going back to page1.php the code to display the form elements in page2.php is
echo "<input type ='hidden' name='username' value='".stripslashes($username)."'>";
echo "<input type =\"text\" name=\"username\" value=\"$username\">";
in page2.php for checkboxes the code is <input type="checkbox" name="" value=""> which is normal html unlike the textfields
above using php
what i have noticed in page2.php is the checkboxes are being validated however the text fields in page2.php do not validate
properly and does not work as it works in page1.php
validating however i am not sure what the exact reason is.
var username = document.registrationform.username
if ((username.value==null) || (username.value=="") || (username.length=="") )
alert("Please Enter a User Name")
if ( (fname.value==null) || (fname.value=="") || (fname.length=="") )
alert("First Name is required")
also sometime if i use fname.value in page2.php i get an error that value is not an object or is null so i have modified the
code in file2.js to some extent
can some one tell me how to go about validating textfields and other form elements in page2.php using php code to be
validated like the checkboxes in page2.php
any help will be greatly appreciated.
also in page2.php i have an insert statement which writes the information that a user has entered in the form into mysql
database. i have read about database injection recently. so i have used $username = addslashes($_POST["username"]);
due to this the value in the database is recorded as example first\name if a user typed first'name in the form should i use
mysql_real_escape_string() method to take extra precaution or is addslashes() method alright. if i adopt
mysql_real_escape_string() do i just read the values simply as $username = mysql_real_escape_string($_POST["username"]);
or do i need to write extra code because of using mysql_real_escape_string() method
02-25-2008, 04:14 PM #2
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- Mar 2007
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username.length=="", fname.length=="" etc should be
BTW, why do you need 3 pages? Submit the form to the same page so that you can easily display the server side validation errors. Just show/hide the html portion depending upon success/failure.
Last edited by abduraooft; 02-26-2008 at 06:22 AM.The Dream is not what you see in sleep; Dream is the thing which doesn't let you sleep. --(Dr. APJ. Abdul Kalam)
02-25-2008, 04:33 PM #3