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Thread: insert problem

  1. #1
    Regular Coder
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    Question insert problem

    hi,i hav a problem here....

    i hav a main page with a button to check overdue records...after i click that button,will redirect to this page and insert the overdue record to another table.but the problem is when i hav 2++ records which are overdue,then redundancy record will occur...

    for eg, 1st overdue record, patientID =1
    2nd overdue record, patientID =2
    3rd overdue record, patientID =2(it will continue insert this record whenever i click that button)

    Code:
    <?php
    	include 'connStr.php';
    	include 'datediff.php';
    
    $query = "SELECT * FROM tblpatient";
    $result = mysql_query($query);
    while ($row = mysql_fetch_array($result)){
    
    $query2 = "Select * from tbloverdue";
    $result2 = mysql_query($query2);
    $row2 = mysql_fetch_assoc($result2);
    
    $TD = $row["Treatment_Date"];
    $patientID = $row["Patient_ID"];
    $overdueID = $row2["Patient_ID"];
    $diff = datediff("$TD","now","m");
    if (($row["Email"]) == ""){
    $row["Email"] = "NO";}
    
    if ($diff > 5 && $patientID != $overdueID){
    
    	$query1 = "Insert into tbloverdue(Patient_ID, Name, Treatment_Date, Email)values('".$row["Patient_ID"]."', '".$row["Name"]."', '".$row["Treatment_Date"]."', '".$row["Email"]."')";
    	$result1 = mysql_query($query1);
    }
    }
    
    	mysql_query("COMMIT");
    
    	echo "<meta http-equiv=\"Content-Type\" content=\"text/html; charset=iso-8859-1\">";
    	echo "<meta http-equiv=\"REFRESH\" content=\"0; URL=overdue.php\">";
    
    ?>
    can somebody pls help me?????

  • #2
    UE Antagonizer Fumigator's Avatar
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    You should either set up the overdue table's primary (unique) key to not allow the duplicate record, or add a query to check to see if that patient is in the table before inserting.


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