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  1. #1
    Senior Coder
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    Regexp replace with function

    I am trying to write a regular expression to match a pattern and replace ti witnh the result of a function. I can get the pattern to match its the function part that is gonig wrong.

    my code

    Code:
    x=x.replace(/(%[0-9][a-z])/g, unescape($1));
    any ideas?

    scroots
    Spammers next time you spam me consider the implications:
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  • #2
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    I believe what you want is:
    Code:
    unescape(RegExp.$1)

  • #3
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    thanks i will try that later on when i'm at home.

    scroots
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  • #4
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    Code:
    var x='string%20here';
    x=x.replace(/(%[0-9a-f]{2})/g, function(m,p){
        return unescape(p);
    }));
    liorean <[lio@wg]>
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  • #5
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    thanks everyone your solutions work, it cleaned up how to pass a regualr epxression value to a function.

    thanks again

    scroots
    Spammers next time you spam me consider the implications:
    (1) that you will be persuaded by me(in a legitimate mannor)
    (2)It is worthless to you, when i have finished


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