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  1. #1
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    Print square of numbers with positions alternating

    Hello. I'm having some troubles with the following problem:

    Write a method called printSquare that takes in two integer parameters, a min and a max, and prints the numbers in the range from min to max inclusive in a square pattern. The square pattern is easier to understand by example than by explanation, so take a look at the sample method calls and their resulting console output in the table below.

    Each line of the square consists of a circular sequence of increasing integers between min and max. Each line prints a different permutation of this sequence. The first line begins with min, the second line begins with min + 1, and so on. When the sequence in any line reaches max, it wraps around back to min.

    You may assume the caller of the method will pass a min and a max parameter such that min is less than or equal to max.
    This is the code I have so far:

    Code:
    public*static*void*printSquare(int*min,int*max){
        for(int*lines=1;lines<=min;lines++){
            for(int*x=min;x<=max;x++){
                System.out.print(x);
            }
            System.out.println();
            min+=1;
        }
    }
    Attached Thumbnails Attached Thumbnails Print square of numbers with positions alternating-screen-shot-2012-07-23-5.34.49-pm.png  

  • #2
    God Emperor Fou-Lu's Avatar
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    You have a long way to go with that one.
    A hint for starters is that min cannot be incremented within the loop since its the control condition for lines to terminate. Doing so will result in an infinite loop.


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