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# Thread: Inclusive Number program not quite working right

1. ## Inclusive Number program not quite working right

This program is working not quite right. now this program is supposed to input five number, and check for any duplication and if there is duplication, it will not show the number. also the number must be between 10 and 100 inclusive. If i enter any number below 10, then it works great, but enter any number after 10, and I can't get it to go to the next input and move forth on. This is what I got:
Code:
```
Enter array:
20
Number entered:
0 21Number entered:
0 21Press any key to continue...```
Code:
```  // compare input number to unique numbers in array
for ( int i = 0; i < counter; i++ )

// if new number is duplicate, do nothing
if ( number == array[ i ] )
return;

// append new number to text area
output.append( " " + number );

// store new and unique number
array[ counter++ ] = number;
}
else
showStatus( "Number entered exceed 5." );

}  // end method actionPerformed

}  // end class Unique```

• Any Suggestion? Anyone?

• How long is the entire program? From what you say it probably isn't that long and you should post the whole thing. In any case, you have to post more code to get any answers. There just isn't enough there for me to help find the problem.

david_kw

• I agree that it's hard to get a good feel for what your issue might be given the minimal code you've provided. However, I will point out one thing that may be an issue.

You don't have any { } for you're for-loop but it looks like (based on the code) that you might want them

If you want more than one operation to be performed in your loop, you need to surround these with brackets. At present your loop should only be performing that following.

Code:
```for ( int i = 0; i < counter; i++ )

// if new number is duplicate, do nothing
if ( number == array[ i ] )
return;```
If you intended your output.append line to be executed for each iteration of the loop you'll need some brackets.

Code:
```for ( int i = 0; i < counter; i++ )
{
// if new number is duplicate, do nothing
if ( number == array[ i ] )
return;

// append new number to text area
output.append( " " + number );

// store new and unique number
array[ counter++ ] = number;
}```

•

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