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Thread: the mean, median and the mode

05022004, 10:12 PM #1
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the mean, median and the mode
hi does any body now a pseudocode to calculate the following:
1) mean
2) median
3) mode
for any 10 random numbers
thanx for any help anyone is abel to provide

05022004, 10:45 PM #2
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Put the numbers into an array.
Mean: add all of the numbers together and divide by 10.
Median: array[4] + array[5] / 2
I'm not sure of a way to calculate the mode though this might help you out:
[http://forums.devshed.com/t46666/s.html]
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05032004, 10:19 AM #3
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Well thinking back to my primary mathematics days mode is the most frequently occurring score ( at least I hope it is ) ...
Now there are a few ways you could go around it. Depending on how many scores you have, the easiest way might be to copy the array of scores into a 2d array and use the second dimension to tally the number of scores of each and then select the one with the greatest scrore.
However the way I would do it would be to sort the scores first (asc or desc whichever your prefer) using whatever method you prefer.. I doubt you have more than say 20 scores so which sort you pick will work fine.
After that counting is easy.
[edit:]
I'm suprised antonio didn't cite you on this but 
Your title could do with a few less exclaimation marks...it's hardly going to make us want to answer your post faster if even at all..
Edit: Removed the exclamation marks from it.
/// lioreanLast edited by liorean; 05032004 at 10:42 AM.
Omnis mico antequam dominus Spookster!

05032004, 10:55 AM #4
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Not all distributions are unimode. If these random numbers are completely randon without dumplicates, then each number will occer once and there is no mode.
If you have 2 number each apearing twice or so, then you'll have a bimodal distribution (2 modes).
So there's no straightforward answer to your question since we don't know anything about the inputvalues.Posting guidelines I use to see if I will spend time to answer your question : http://www.catb.org/~esr/faqs/smartquestions.html

05032004, 11:55 AM #5
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So thay first need to be split up in groups of 10 elements? (according to your original question) So then you get
9,5,6,23,25,22,12,12,2,2 as the first group, which means you'll have 2 modi : 2 and 12
so your steps are :
 sort element
 count each values occurence
 sort frequecys descending
 report value with heighest frequence.
 check if the next value has the same frequency and if so, also report it.Posting guidelines I use to see if I will spend time to answer your question : http://www.catb.org/~esr/faqs/smartquestions.html