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Thread: Arithmetic Operation Problem

09242011, 08:32 AM #1
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Arithmetic Operation Problem
hello Every one,
Today my problem is much complex for me, I am so confused why is this happening;
The problem is
if i have a = 2;
********** In C Language **********
and i perform
i = a++ + ++a + a + a + ++a;
then result is = 15
i = a++ + ++a + a + a;
then result is = 8
************ In Java Language ************
i = a++ + ++a + a + a + ++a;
then result is = 15
i = a++ + ++a + a + a;
then result is = 12
I don't know why is this happening, what is the reasion, I am performing the same operation but the result is different.
Please give me the detail description about this.
Thank You.

09242011, 06:03 PM #2
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thats interseting,
make sure you that the initial value of a is the same in java and in c
try to divide it with brackets
i = (a++) + (++a) + (a) + (a);
and see if that makes a difference

09252011, 07:11 AM #3
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Thanks for your reply chris0.
But the problem is same as it is yet.
for the java the program is
public class test {
public static void main(String ar[]) {
int a=2,j=0,k=0;
j = a++ + ++a + a + a + ++a;
k = a++ + ++a + a + a;
System.out.println("The value of j = " + j + " and the value of k = " + k);
}
}
then the result is
The value of j = 15 and the value of k = 12
Also if i seperate all of them with parenthesis like you told (a++) then the
result is same.
for c the program is
int main(void)
{
int a=2,j=0,k=0;
clrscr();
j = a++ + ++a + a + a + ++a;
k = a++ + ++a + a + a;
printf("The value of j = %d and the value of k = %d", j,k);
getch();
return 0;
}
then the result is
The value of j = 15 and the value of k =8
I used parenthesis Alos, but nothing happened.
Please give me the detail description about this problem.
thank you.