View Full Version : Chaining methods
07-10-2006, 01:44 PM
I can't figure out how this is done, does anyone have a simplified example?
07-10-2006, 03:28 PM
That notation isn't chaining of methods.
What is happening there is you have an object being returned by $. That object has a method called html, which is being called. That method returns an object that has the method show, which is being called. Expanded it looks like:
var x = $('element');
var y = x.html('blah');
But because $ returns a pointer, there's no reason to store it in x:
var y = $('element').html('blah');
But the same is true for html, it returns a pointer to an object, why store it?
Hope that clears it up.
07-10-2006, 03:48 PM
Well, you can do :
so the order of the functions doesn't matter. There are also no duplicate functions.
07-10-2006, 03:54 PM
I assure you that your library cannot change the rules of the language, this is object notation, and those are methods being called on objects.
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