Wrong parameter count for mysql_query

[thesavior]

this is my code:


$biggestreferer = 'SELECT referer, COUNT(*) AS p FROM admin_stats WHERE referer != "" GROUP BY referer ORDER BY p DESC LIMIT 1';
$biggestreferer = mysql_query($biggestreferer) or exit (mysql_error());
$biggestreferer = mysql_result($biggestreferer);

and it is for some reason returning a php error, not a mysql error. Mysql doesn't have a problem with the query and i have tried it in phpmyadmin and it works. Here is my php error:


Warning: Wrong parameter count for mysql_result() in /raid5/home/eli/public_html/newhome/administration/stats.php on line 35


What is the problem with this?

[harsh789]

you forget to pass row param in mysql_result statement.
$biggestreferer = mysql_result($biggestreferer,0);

[lavinpj1]

http://uk2.php.net/mysql_result

Always try reading the php manual. It tells you exactly which parameters are needed.

~Phil~