Even + method

[NichoLe]

Good Afternoon all ...

Ive beeen trying this question out for 2 days now but no improvment i might be losing it or something ... can someone help

1- Create the class Even. It should contain two methods:

isEven: The method should take an integer argument and return true if the integer in even and false otherwise. The method should use the reminder operator to determine if the integer is even or not.

The main method should ask the user to input a number and it will call the isEven method to check if it is even or not. If the number is even the maid method will display "YOU ENTERED AN EVEN NUMBER" If the number is odd the mmain method should continue to ask the user to input numbers until he enters "0".



This is what i did




import javax.swing.JOptionPane;

class Even
{
public static void main (String args[])
{

String Num1;
int number1, num;

Num1= JOptionPane.showInputDialog("Enter a number: ");
number1 = Integer.parseInt(Num1);

isEven(num);

System.exit( 0 );

}

static void isEven(int a)
{

if ( a % 2 == 1)

{
JOptionPane.showMessageDialog(null, "You entered an even number " + a);
}

else if ( a % 2 == 0)
{
JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
}


}//isEven()
}//end main




Please tell me if am on the wrong track!!

[shmoove]

Your isEven method is reversed. If a number can be divided by 2 with no remainder then that number is even - hence (a % 2 == 0) => a is even.

Other than that, you haven't filled the requirements of your homework to the letter:
1) The isEven method should return a boolean value (true or false) and not be the one printing the statement (that should be in main).
2) The main method should have a while loop so that it can keep asking for input until the user enters an even number.

shmoove

[NichoLe]

Thank you bro ...


i tried this ... :confused:


import javax.swing.JOptionPane;

class Even
{
public static void main (String args[])
{

String Num1;
int number1;

//run a loop for this to go for ever unless user enters 0

while(true)
{

Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\nOr Enter a number: ");
number1 = Integer.parseInt(Num1);

if(number1<=0)
{

System.exit(0);
}

else{
isEven(number1);
}
}//end loop



static void isEven(int a)
{

if ( a % 2 == 1)

{
JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
}

else if ( a % 2 == 0)
{
JOptionPane.showMessageDialog(null, "You entered an even number " + a);
}


}//isEven()
}//end main

[shmoove]

Better. But again, the assignment asks for an isEven() method that returns a boolean value:

isEven(number)
if number is even return true
if number is odd return false

Then you can use it in a conditional statement inside main():

if (isEven(someNumber))
print out "It's even"
else
print out "It's odd"


shmoove

[NichoLe]

it worked :D


import javax.swing.JOptionPane;

class Even
{
public static void main (String args[])
{
String Num1;
int number1;

//run a loop for this to go for ever unless user enters 0
while(true)
{
Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\n" +
"Or Enter a number: ");
number1 = Integer.parseInt(Num1);

if(number1<=0)
System.exit(0);
else
isEven(number1);
}//end loop
}// end main

static void isEven(int a)
{
if ( a % 2 == 1)
JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
else if ( a % 2 == 0)
JOptionPane.showMessageDialog(null, "You entered an even number " + a);
}//isEven()
}//end class



Letz party

[Roelf]

But not as you were told to do:

isEven: The method should take an integer argument and return true if the integer in even and false otherwise. The method should use the reminder operator to determine if the integer is even or not.

your IsEven method does not return anything (void). It just outputs some text to a userinterface


The main method should ask the user to input a number and it will call the isEven method to check if it is even or not. If the number is even the maid method will display "YOU ENTERED AN EVEN NUMBER" If the number is odd the mmain method should continue to ask the user to input numbers until he enters "0".
the outputting of your IsEven method should be done by the main method

Please tell me if am on the wrong track!!
you are a bit on the wrong track, follow shmoove's hints and you will be graded better than you will be now

[NichoLe]

mmmmmmmmmmm .. am confused now ... :(

ill try 2 follow ur hints

[hinokata]

public boolean thisIsABigHint();

[Roelf]

main(){
if (thisIsABigHint()) {
it sure is;
} else {
perhaps NicholE needs more hints
}
}

[NichoLe]

Thank you i submitted it :]

[Roelf]

which one did you submit, the last posted version? Or an improved version which meets the requirements?

[NichoLe]

This one

class Even
{
public static void main (String args[])
{
String Num1;
int number1;

//run a loop for this to go for ever unless user enters 0
while(true)
{
Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\n" +
"Or Enter a number: ");
number1 = Integer.parseInt(Num1);

if(number1<=0)
System.exit(0);
else
isEven(number1);
}//end loop
}// end main

static void isEven(int a)
{
if ( a % 2 == 1)
JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
else if ( a % 2 == 0)
JOptionPane.showMessageDialog(null, "You entered an even number " + a);
}//isEven()
}//end class


why :confused:

[Roelf]

your isEven should look like this:

public static boolean isEven(int a)
{
if ( a % 2 == 1) {
// the number is odd, so return false
return (false);
} else {
// the number is even, so return true
return (true);
}
}//isEven()


that way it returns a boolean, true if the supplied argument is even and false if it is odd.
Now you can ask in the main method whether a number is odd or even by doing:
if (isEven(number)) {
// the number is even
} else {
// the number is odd
}

[NichoLe]

Thank you soooooooo much ..