cwl157
11242004, 03:28 PM
how do i find an exponent in java i think its the math.pow() method can someone show me an example of how to call this method correctly.


View Full Version : finding exponents in java cwl157 11242004, 03:28 PM how do i find an exponent in java i think its the math.pow() method can someone show me an example of how to call this method correctly. Antoniohawk 11242004, 06:17 PM Google is your friend. [http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Math.html#pow(double,%20double)] cwl157 11242004, 06:19 PM yea i was looking at the pow() method but i dont know how to use it cause i have to take a number as input from the user and raise it to a power so how would i do that? Can i make a variable one of the parameters in the method? Antoniohawk 11242004, 06:24 PM Yup. :) turbowrx 11242004, 06:54 PM Both parameters are variables. Reading the api you'll notice that it returns a double. x = Math.pow(y, z); You'll get z to the yth power. That is not finding an exponent. What do you mean by finding an exponent? cwl157 11242004, 07:00 PM yea sorry what you described is what i want to do. sorry my mind is pretty shot right now cause ive been working on this for hours and i just want to finish it. JWizard 02022005, 11:43 PM Math.pow(double y,double z) returns a double value of y raised to the zth power, not the other way around, as turbowrx has said. Since we're being technical. cfc 02032005, 02:01 AM Perhaps logarithms could be of some use? double exp = Math.log10(double number) / Math.log10(double base); I just realized Math.log is base e, so I switched it to Math.log10 
 
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