java help

Hi guys & gals,

Is there a way in Java that I can convert a double type number such as 3.1111111111222 to only two decimal places? So it would be as 3.11 only?

Another question is how to do Stop a method from running in Java Code?

For example.. I'm doing a loop.. and a user input a 'char' type.
If it's match.. it stop excute.. other while it keeps going.

I know have to use input, and if and else statement.

Which I already did.. But I need a method to stop from running..

Please help...

Thank you so much.

I'm not sure about your first question but I'm sure if you check the documentation for the Math class, and the Double and Float classes you'll find something. As a last resort you can always multiply the number by 100, floor() or round() it to an integer, and then divide by 100.

About the second question:
You should add a variable that tells the loop if it should continue running. Then you write you loop like so:

while (running) {
// do something
}

Then the input handler just has to set the variable running to false, and the execution of the loop won't continue.

shmoove

something tells me you are tryin to find pi using the vieta method...i had to do a similar assignment at uni.

check out the double class at...

http://java.sun.com/j2se/1.4/docs/api/index.html

there should be a roundup/down method attached somewhere

[code]
int the_number=3.1111111111222;
//the number...

String num=""+3.1111111111222+"";
//turn the number to a string

String new=num.indexOf(0)+num.indexOf(1)+num.indexOf(2)+num.indexOf(3);
//grabs the first 4 characters(including the dot)

int final_number=parseInt(new);
//turns the string to an integer

thats a bad way to do it, but it will work