problem

[g0liatH]

I made a script:


<form>
<SELECT name="test">
<OPTION value="1">1</OPTION>
<OPTION value="2">2</OPTION>
<OPTION value="3">3</OPTION>
</SELECT><BR></form>



<? if ($_POST['test'] = 2 ) {

$template = "ATGtemp";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
else {
echo "testtest";
}
?>


these 2 codes are in 1 file.

I always get include() and I never get "testtest"
What do I have to change in the script so it wont always show include() ???

[mordred]

if ($_POST['test'] = 2 )


is most certainly a typo. What you are doing there is assigning the number 2 to $_POST['test'] by using one equals sign. This assignment always succeeds, so it evaluates as true. What you need is to use two equals signs to compare for equality:


if ($_POST['test'] == 2 )


If you happen to make this mistake often, here's a trick that works the same as the above code, but if you use one equals sign you get a PHP error:


if (2 == $_POST['test'])

[Spookster]

I'm not sure how you even get that. Your expression in your if statement is incorrect

if ($_POST['test'] = 2

should probably be

if ($_POST['test'] == "2")

[mordred]

And if you define your form tag without the method="post" attribute, all incoming form data will be by GET, and thus in the $_GET array.

[g0liatH]

ok thx guys :thumbsup: I kno im a n00b :o

[g0liatH]

I used the script now and it works but there is still 1 problem.
If i click "post comment", the script goes back to the first page:confused:

you can see it yourself here:
http://www.alltimegaming.com/phptest/testform2.php
and if I click the submit button again, it works...

this is the new code:

<form method="post">
<SELECT name="test">
<OPTION value="1">Show All</OPTION>
<OPTION value="2">General</OPTION>
<OPTION value="3">Gaming</OPTION>
<OPTION value="4">Site</OPTION>
<OPTION value="5">Events</OPTION>
</SELECT><BR>
<input type="submit" value="Submit">
</form>
<? if ($test == 1 ) {
$template = "ATGtemp";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
elseif ($test == 2 ) {
$template = "ATGtemp";
$category= "3";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
elseif ($test == 3 ) {
$template = "ATGtemp";
$category= "4";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
elseif ($test == 4 ) {
$template = "ATGtemp";
$category= "5";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
elseif ($test == 5 ) {
$template = "ATGtemp";
$category= "6";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}

?>


Do u know what the problem is? Is there a else {} command to continue the link?

[Nightfire]

<form method="post">
<SELECT name="test">
<OPTION value="1">Show All</OPTION>
<OPTION value="2">General</OPTION>
<OPTION value="3">Gaming</OPTION>
<OPTION value="4">Site</OPTION>
<OPTION value="5">Events</OPTION>
</SELECT><BR>
<input type="submit" value="Submit">
</form>
<?php

$test = $_POST['test'];

if ($test == 1 ) {
$template = "ATGtemp";
include("/home/virtual/site51/fst/var/www/html/news2/show_news.php");
}
..... etc etc etc ..........

[g0liatH]

It doesn't help. I still have to click submit until I can post a comment

[Nightfire]

I dunno where your problem is, I don't even see a post comment on that form or code you're showing

[g0liatH]

if you click on gaming or show all or whatever, you see news, and on every newspost u see "comments", if you click on that, you just go to a white page instead of the page u should go and if u then click submit, u go to the real page.

[mordred]

If you mean by "Post Comment" the link titled "comments", then you get the data per GET parameters. Links are not forms and their query string does not appear in the $_POST array. Does that help?

[g0liatH]

yea i mean the link "comments". so u are saying I have to change
<form method="post"> to <form method="get">
?

[g0liatH]

w00t finally it works!!:D

thx everyone who helped me:)