tridentspk

12-06-2011, 06:04 AM

Hey guys,

So I have this last question in my python lab

Its question # 6 on this page (on the right hand column):

http://goo.gl/rqDwS

My problem is figuring out how to make a loop that checks for each number between 1 and the input N.

For example, if N = 12, I'll need to print a table of numbers from 1-12 and displaying whether each number is perfect, abundant, or deficient.

So far I have only written code that determines what status the value of input N is.

def print_table(n):

i = 1

add = 0

last = n - 1

count = n

while i <= last:

if count % i == 0:

add = add + i

i = i + 1

msg = ''

if add < n:

msg = 'is deficient'

elif add == n:

msg = 'is perfect'

elif add > n:

msg = 'is abundant'

print n, msg

number = int(input("Enter a number: "))

print_table(number)

The output of the program should look like this:

Enter a number: 12

12 abundant

11 deficient

10 deficient

9 deficient

8 deficient

7 deficient

6 perfect

5 deficient

4 deficient

3 deficient

2 deficient

1 perfect

Now here is the logic behind it:

12 < 1 + 2 + 3 + 4 + 6

11 > 1

10 > 1 + 2 + 5

9 > 1 + 3

8 > 1 + 2 + 4

7 > 1

6 = 1 + 2 + 3

5 > 1

4 > 1 + 2

3 > 1

2 > 1

1 = 1

So thats why I was thinking of having some kind of while loop that produces different variables like add11, add10, add9, etc to store the sum of the numbers that leave a remainder of 0. But that doesn't seem to be possible.

Thanks for any help on this :)

So I have this last question in my python lab

Its question # 6 on this page (on the right hand column):

http://goo.gl/rqDwS

My problem is figuring out how to make a loop that checks for each number between 1 and the input N.

For example, if N = 12, I'll need to print a table of numbers from 1-12 and displaying whether each number is perfect, abundant, or deficient.

So far I have only written code that determines what status the value of input N is.

def print_table(n):

i = 1

add = 0

last = n - 1

count = n

while i <= last:

if count % i == 0:

add = add + i

i = i + 1

msg = ''

if add < n:

msg = 'is deficient'

elif add == n:

msg = 'is perfect'

elif add > n:

msg = 'is abundant'

print n, msg

number = int(input("Enter a number: "))

print_table(number)

The output of the program should look like this:

Enter a number: 12

12 abundant

11 deficient

10 deficient

9 deficient

8 deficient

7 deficient

6 perfect

5 deficient

4 deficient

3 deficient

2 deficient

1 perfect

Now here is the logic behind it:

12 < 1 + 2 + 3 + 4 + 6

11 > 1

10 > 1 + 2 + 5

9 > 1 + 3

8 > 1 + 2 + 4

7 > 1

6 = 1 + 2 + 3

5 > 1

4 > 1 + 2

3 > 1

2 > 1

1 = 1

So thats why I was thinking of having some kind of while loop that produces different variables like add11, add10, add9, etc to store the sum of the numbers that leave a remainder of 0. But that doesn't seem to be possible.

Thanks for any help on this :)