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View Full Version : Using two functions on one echo?



likeskoolaid
09-03-2011, 11:47 PM
I have two functions, one turns un-href links into working href links.




<?php
$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";
?>


The other replaces an array of words into a different word.



<?php
$replace = array(
'Cat' => 'Dog',
);
?>



This is how you echo both separately, the problem I'm having and need help with is combining both functions into one echo so both fixes apply to a single variable ($content).




<?php echo str_replace_assoc($replace,$content); ?>

<?php echo preg_replace(a$reg_exUrl, '<a href="'.$url[0].'" target="_blank" class="outboundlink" rel="nofollow">'.$url[0].'</a>', $content); ?>

mlseim
09-04-2011, 12:34 AM
Did you try this .. I'm just guessing here ...

<?php echo preg_replace(a$reg_exUrl, '<a href="'.$url[0].'" rel="nofollow" target="_blank" class="outboundlink" rel="nofollow">'.$url[0].'</a>', str_replace_assoc($replace,$content)); ?>


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