jquery

sometimes when running

$.ajax({
url: urltoajax,
cache: false,
success: function(html) {
$("#formfields").html(html);
}
});

in jquery from a link

meaning i call my javascript function on click of the link - instead of replacing the div it ads a new one with the new content
it should replace the div called #formfields

sometimes when running

$.ajax({
url: urltoajax,
cache: false,
success: function(html) {
$("#formfields").html(html);
}
});

in jquery from a link

meaning i call my javascript function on click of the link - instead of replacing the div it ads a new one with the new content
it should replace the div called #formfields
put your code between [ code] and [ /code] tags, please.

try this way:

$.ajax({
url: urltoajax,
cache: false,
success: function(data) {
$("#formfields").replace(data);
}
});


best regards

this gives me an error

this gives me an error
i didn't test it, and now i just look thru jquery docs, is replaceWith

http://api.jquery.com/replaceWith/

try this and if you get an error, post the error to.

forget to say, was my fault, :)
best regards