webcom8
04-21-2003, 11:26 PM
In the following script, I have been told, “window name should be different for each”. How do I name each window? Could someone point me further along with an example of the correct code. My attempt brought up errors.
Thanks,
Thomas
<script>
function openpopup(){
var popurl="comm1.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm2.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm3.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm4.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm5.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
:(
Thanks,
Thomas
<script>
function openpopup(){
var popurl="comm1.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm2.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm3.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm4.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm5.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
:(