webcom8
04-20-2003, 04:41 AM
The variable “popurl” is “comm1.htm” through “comm5.htm”. Only the “comm5.htm”, being the last popup on the page, will open for all of the, five, popup links. How can I get each popup to open it’s own respective page?
Example follows.
Thanks for any answers.
<script>
function openpopup(){
var popurl="comm1.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm2.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm3.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm4.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm5.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
Example follows.
Thanks for any answers.
<script>
function openpopup(){
var popurl="comm1.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm2.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm3.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm4.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>
<script>
function openpopup(){
var popurl="comm5.htm"
winpops=window.open(popurl,"","width=480,height=450,status,")
}
</script>